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.asp MS SQL unique identifier generator - getting duplicates

I am trying to generate some unique identifiers through .asp and I am getting duplicates.  I could need up to 2000 of them.  The reason I am generating it because I have to reference that GUID in another table.  How can I make sure I am getting non duplicates?

Function CreateWindowsGUID()
  CreateWindowsGUID = CreateGUID(8) & "-" & _
    CreateGUID(4) & "-" & _
    CreateGUID(4) & "-" & _
    CreateGUID(4) & "-" & _
    CreateGUID(12)
End Function

Function CreateGUID(tmpLength)
  Randomize Timer
  Dim tmpCounter,tmpGUID
  Const strValid = "0123456789ABCDEF"
  For tmpCounter = 1 To tmpLength
    tmpGUID = tmpGUID & Mid(strValid, Int(Rnd(1) * Len(strValid)) + 1, 1)
  Next
  CreateGUID = tmpGUID
End Function

Open in new window


Thanks.

/****** GUID = CAC8CD83-A0A3-A39E-4E4A-E55EEB3FC73D
/****** GUID = 7B975254-5062-545C-EF08-851D7100F775
/****** GUID = 1C55E816-BB0C-F42B-90D7-36EC06D227BD
/****** GUID = CD247DE7-5BCA-A5E9-3196-E7AA9CA35605
/****** GUID = 6EE303B9-0C89-46A8-AB3F-88692175864D
/****** GUID = 1FA1988A-BD58-F777-4CFE-3938B746C685
/****** GUID = BF703E5C-5E16-9835-FCBD-93C1B0AC57BD
/****** GUID = 603EC32D-0FD5-4804-9D8B-3490567D97F5
/****** GUID = CAC8CD83-A0A3-A39E-4E4A-E55EEB3FC73D
/****** GUID = 7B975254-5062-545C-EF08-851D7100F775
/****** GUID = 1C55E816-BB0C-F42B-90D7-36EC06D227BD
/****** GUID = CD247DE7-5BCA-A5E9-3196-E7AA9CA35605
/****** GUID = 6EE303B9-0C89-46A8-AB3F-88692175864D
/****** GUID = 1FA1988A-BD58-F777-4CFE-3938B746C685
/****** GUID = BF703E5C-5E16-9835-FCBD-93C1B0AC57BD
/****** GUID = 603EC32D-0FD5-4804-9D8B-3490567D97F5
/****** GUID = CAC8CD83-A0A3-A39E-4E4A-E55EEB3FC73D
/****** GUID = 7B975254-5062-545C-EF08-851D7100F775
/****** GUID = 1C55E816-BB0C-F42B-90D7-36EC06D227BD
/****** GUID = CD247DE7-5BCA-A5E9-3196-E7AA9CA35605
/****** GUID = 6EE303B9-0C89-46A8-AB3F-88692175864D
/****** GUID = 1FA1988A-BD58-F777-4CFE-3938B746C685
/****** GUID = BF703E5C-5E16-9835-FCBD-93C1B0AC57BD
/****** GUID = 603EC32D-0FD5-4804-9D8B-3490567D97F5
/****** GUID = CAC8CD83-A0A3-A39E-4E4A-E55EEB3FC73D
/****** GUID = 7B975254-5062-545C-EF08-851D7100F775
/****** GUID = 1C55E816-F121-4B50-D6FC-7D01924DC6DE
/****** GUID = 03490963-A2FF-EC1E-87CB-2EDF271FF516
/****** GUID = B4189E24-43BE-9DDD-E154-CE9EBDE0255E
/****** GUID = 55D634F6-F47D-3DAC-8223-7F5D52B25596
/****** GUID = 0695C9C7-944B-EE6A-33E2-D9F65C18F6CE
/****** GUID = A7635F99-450A-8F29-D4A0-8AB5E1E92606
/****** GUID = 11FD59FF-E6C8-F9C3-857F-2B8377BA565E
/****** GUID = B2CCEEC0-9797-9A81-253D-DC420C8C8696
/****** GUID = 638A7492-F121-4B50-D6FC-7D01924DC6DE
/****** GUID = 03490963-A2FF-EC1E-87CB-2EDF271FF516
/****** GUID = B4189E24-43BE-9DDD-E154-CE9EBDE0255E
/****** GUID = 55D634F6-F47D-3DAC-8223-7F5D52B25596
/****** GUID = 0695C9C7-944B-EE6A-33E2-D9F65C18F6CE
/****** GUID = A7635F99-450A-8F29-D4A0-8AB5E1E92606
/****** GUID = 11FD59FF-E6C8-F9C3-857F-2B8377BA565E
0
DMTechGrooup
Asked:
DMTechGrooup
  • 3
2 Solutions
 
Scott Fell, EE MVEDeveloperCommented:
If you are using mssql server, you can create a field type uniquidentifier and set the default value to newid() and a unique guid will be generated.  

You can also simply generate random characters in asp, then update your db.  For the field that you are going to update, create a new index on it and make the index unique.  When setting up the index, click on the options tab on the left  (assuming you are in sql manager) and find the general section in the main part of the window and set Ignore Duplicates to True.

Finally generate your random characters and loop through 3000 times and exit the loop when the row count gets to 2000.
0
 
Big MontySenior Web Developer / CEO of ExchangeTree.org Commented:
here is a simple function that'll generate a 14 random char GUID for you by using the current date/time:

<%@LANGUAGE="VBSCRIPT"%>
<HTML>
<BODY>
<%

Response.Write "GUID = " & CreateGUID()

Function CreateGUID()
  Dim tmpTemp
  tmpTemp = Right(String(4,48) & Year(Now()),4)
  tmpTemp = tmpTemp & Right(String(4,48) & Month(Now()),2)
  tmpTemp = tmpTemp & Right(String(4,48) & Day(Now()),2)
  tmpTemp = tmpTemp & Right(String(4,48) & Hour(Now()),2)
  tmpTemp = tmpTemp & Right(String(4,48) & Minute(Now()),2)
  tmpTemp = tmpTemp & Right(String(4,48) & Second(Now()),2)
  CreateGUID = tmpTemp
End Function
%>
</BODY>
</HTML>

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http://support.microsoft.com/kb/320375

that article also has functions that'll use a time offset if you want more "uniqueness"
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Scott Fell, EE MVEDeveloperCommented:
Correction: "the main part of the window and set Ignore Duplicates to True"  should be to False
0
 
DMTechGrooupAuthor Commented:
Thanks.. I actually created the record and let SQL create the UID.. then did a select on that record to get the UID for my other insert functions.
0
 
Scott Fell, EE MVEDeveloperCommented:
Good choice.   I  believe that guid will be unique for the entire database, not just the table.
0

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