Solved

Count statement with group...

Posted on 2014-12-17
5
110 Views
Last Modified: 2014-12-18
Hello, can someone let me know how I can write a statement that firsts groups by column A and then give a count of values in column B. For eg;
Col-A(Cust ID)         Col-B
100                          Closed
200                          Active  
200                          Active
100                          Closed
300                          Open
400                          Progress
500                          Active

Output I am looking for is:
Col-B   count
Closed  1
Active    2
Open     1
Progress 1

Thanks for the help.

A
0
Comment
Question by:aej1973
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
  • 2
5 Comments
 
LVL 65

Expert Comment

by:Jim Horn
ID: 40506257
> firsts groups by column A and then give a count of values in column B.
Not quite sure I'm following your logic here, as the sample data set doesn't translate to the data mockup.  
There are seven rows in your sample data set, and only five in the result set.
Select ColB, COUNT(ColB) as the_count
FROM YourTable
GROUP BY ColB

Open in new window

0
 

Author Comment

by:aej1973
ID: 40506280
I am sorry if I did not make myself clear. Let me explain;

The first grouping should be with reference to  Col-A. So the outcome would be:
Col-A Col-B
100    Closed
200    Active
300    Open
400    Progress
500   Active

The next grouping and count should be with reference to col-B, the output will be;
Col b      count
Closed     1
Active      2
Open       1
progress 1

How can these two steps be combined into one query? Thanks for taking a look at it.

A
0
 
LVL 65

Accepted Solution

by:
Jim Horn earned 500 total points
ID: 40506313
Okay, try this then:
IF OBJECT_ID('tempdb..#tmp') IS NOT NULL
   DROP TABLE #tmp
GO

CREATE TABLE #tmp (ColA int, ColB varchar(25)) 

INSERT INTO #tmp (ColA, ColB)
VALUES 
   (100, 'Closed'), (200, 'Active'),  (200, 'Active'),(100, 'Closed'),
   (300, 'Open'),(400, 'Progress'),(500, 'Active')

SELECT a.ColB, COUNT(a.ColB) as [Count]
FROM (
   Select ColA, ColB
   FROM #tmp
   GROUP BY ColA, ColB) a
GROUP BY a.ColB

Open in new window

0
 
LVL 25

Expert Comment

by:chaau
ID: 40508156
All you need is to count DISTINCT values, like this:
Select ColB, COUNT(DISTINCT ColA) as the_count
FROM YourTable
GROUP BY ColB

Open in new window

0
 

Author Closing Comment

by:aej1973
ID: 40508274
Works! Thank you.
0

Featured Post

NFR key for Veeam Backup for Microsoft Office 365

Veeam is happy to provide a free NFR license (for 1 year, up to 10 users). This license allows for the non‑production use of Veeam Backup for Microsoft Office 365 in your home lab without any feature limitations.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Introduction In this installment of my SQL tidbits, I will be looking at parsing Extensible Markup Language (XML) directly passed as string parameters to MySQL 5.1.5 or higher. These would be instances where LOAD_FILE (http://dev.mysql.com/doc/refm…
Introduction This article is intended for those who are new to PHP error handling (https://www.experts-exchange.com/articles/11769/And-by-the-way-I-am-New-to-PHP.html).  It addresses one of the most common problems that plague beginning PHP develop…
Exchange organizations may use the Journaling Agent of the Transport Service to archive messages going through Exchange. However, if the Transport Service is integrated with some email content management application (such as an antispam), the admini…

733 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question