Solved

unpivot calculated columns to rows, unkown column names

Posted on 2014-12-18
2
103 Views
Last Modified: 2014-12-23
Hi, I have a table similar to the one below, I need to unpivot the table to that there would be 4 column, and a row would look like
The other issue, I'm facing is that there is an unknown number of rows, so I will somehow have to create a dynamic comma delimited list of column names from the table.
If anyone has a script to do this would be super appreciated!
~thank you in advance

PeriodType, PeriodValue, AgentNo, Metric, Value
Year           2014           EY57627   Metric1  1833
Year           2014           EY57627   Metric2   609.87
Year           2014           EY57627   Metric3   0.804878

     IF OBJECT_ID('TempDB..#mytable','U') IS NOT NULL
         DROP TABLE #mytable

--===== Create the test table with 
 CREATE TABLE #mytable 
        (
        PeriodType Varchar(50),
        PeriodValue varchar(50),
        AgentNo varchar(10),
        Metric1 varchar(50),
        Metric2 varchar(50),
        Metric3 varchar(50)
        )
       
       insert into #mytable 
       (PeriodType, PeriodValue, AgentNo, Metric1, Metric2, Metric3)
 SELECT 'Year','2014','EY57627','1833','609.87','0.804878' UNION ALL
SELECT 'Year','2014','EY37480','11784','401.413','0.833333' UNION ALL
SELECT 'Year','2014','EY37715','0','0','0' UNION ALL
SELECT 'Year','2014','6069748','8242','479.842','0.857542' UNION ALL
SELECT 'Year','2014','ex51539','0','0','0' UNION ALL
SELECT 'Year','2014','6071493','4833','594.724','0.7866' UNION ALL
SELECT 'Year','2014','EY58441','0','0','0' UNION ALL
SELECT 'Year','2014','EY46081','0','0','0' UNION ALL
SELECT 'Year','2014','EY38615','910','729.865','0.707865' UNION ALL
SELECT 'Year','2014','EY38864','3786','402.036','0.869674' UNION ALL
SELECT 'Year','2014','EY35608','824','886.701','0.791667' UNION ALL
SELECT 'Year','2014','EY53571','37','904.568','0.75' UNION ALL
SELECT 'Year','2014','EY11014','0','0','0' UNION ALL
SELECT 'Year','2014','EY13297','537','583.872','0.877193' UNION ALL
SELECT 'Year','2014','6010922','597','607.787','0.770833' UNION ALL
SELECT 'Year','2014','6027444','5255','299.85','0' UNION ALL
SELECT 'Year','2014','6027814','5830','678.576','0.709125' UNION ALL
SELECT 'Year','2014','EY54924','801','600.402','0.631579' UNION ALL
SELECT 'Year','2014','EY35642','2693','613.134','0.773913' UNION ALL
SELECT 'Year','2014','EY57364','0','0','0' UNION ALL
SELECT 'Year','2014','6072995','707','544.037','0.766667' UNION ALL
SELECT 'Year','2014','EY24392','9110','392.218','0.817299' UNION ALL
SELECT 'Year','2014','EY44314','5908','734.806','0.808905' UNION ALL
SELECT 'Year','2014','EY39344','7352','520.189','0.820922' UNION ALL
SELECT 'Year','2014','EX89538','5931','423.479','0.75'

Open in new window

0
Comment
Question by:Scarlett72
2 Comments
 

Author Comment

by:Scarlett72
Comment Utility
Ok, I came across this script below, but I am getting the following error, is there any way to resolve this?

Query generated:

SELECT *
FROM dbo.t_OutlierCalc_BM
UNPIVOT (
    value FOR code IN (
        [PeriodType], [PeriodValue], [emp_no], [CallsHandled], [AverageHandlingTime], [CsatTop2], [CsatBottom2], [ResolutionTop2], [ResolutionBottom2], [FCR_7], [FCR_7_WithTransfer]
    )
) unpiv

Open in new window


The type of column "PeriodValue" conflicts with the type of other columns specified in the UNPIVOT list.

DECLARE @table_name SYSNAME
SELECT @table_name = 'dbo.t_OutlierCalc_BM'
 
DECLARE @SQL NVARCHAR(MAX)
SELECT @SQL = '
SELECT *
FROM ' + @table_name + '
UNPIVOT (
    value FOR code IN (
        ' + STUFF((
    SELECT ', [' + c.name + ']'
    FROM sys.columns c WITH(NOLOCK)
    LEFT JOIN (
        SELECT i.[object_id], i.column_id
        FROM sys.index_columns i WITH(NOLOCK)
        WHERE i.index_id = 1
    ) i ON c.[object_id] = i.[object_id] AND c.column_id = i.column_id
    WHERE c.[object_id] = OBJECT_ID(@table_name)
        AND i.[object_id] IS NULL
    FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 2, '') + '
    )
) unpiv'
 
PRINT @SQL
EXEC sys.sp_executesql @SQL

Open in new window

0
 
LVL 24

Accepted Solution

by:
chaau earned 500 total points
Comment Utility
I fixed your code. Please note that I have adjusted it for TempDB..#myTable. Remove TempDB from sys.columns and sys.index_columns for your database:
SELECT *
FROM #mytable
UNPIVOT (
    value FOR code IN (
        [Metric1], [Metric2], [Metric3]
    )
) unpiv
                                          
DECLARE @table_name SYSNAME
SELECT @table_name = 'TempDB..#mytable'
 
DECLARE @SQL NVARCHAR(MAX)
SELECT @SQL = '
SELECT *
FROM ' + @table_name + '
UNPIVOT (
    value FOR code IN (
        ' + STUFF((
    SELECT ', [' + c.name + ']'
    FROM TempDB.sys.columns c WITH(NOLOCK)
    LEFT JOIN (
        SELECT i.[object_id], i.column_id
        FROM TempDB.sys.index_columns i WITH(NOLOCK)
        WHERE i.index_id = 1
    ) i ON c.[object_id] = i.[object_id] AND c.column_id = i.column_id
    WHERE c.[object_id] = OBJECT_ID('TempDB..#mytable')
        AND i.[object_id] IS NULL
		AND c.name NOT IN('PeriodType', 'PeriodValue', 'AgentNo')
    FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 2, '') + '
    )
) unpiv'
 
PRINT @SQL
EXEC sys.sp_executesql @SQL

Open in new window

0

Featured Post

IT, Stop Being Called Into Every Meeting

Highfive is so simple that setting up every meeting room takes just minutes and every employee will be able to start or join a call from any room with ease. Never be called into a meeting just to get it started again. This is how video conferencing should work!

Join & Write a Comment

Suggested Solutions

Title # Comments Views Activity
SQL 2012 Syntax Error 5 23
Numeric sequence in SQL 14 36
SQL Help - 12 36
SQL Server can be started but not accessed 1 14
In this article I will describe the Copy Database Wizard method as one possible migration process and I will add the extra tasks needed for an upgrade when and where is applied so it will cover all.
How to leverage one TLS certificate to encrypt Microsoft SQL traffic and Remote Desktop Services, versus creating multiple tickets for the same server.
This video shows how to set up a shell script to accept a positional parameter when called, pass that to a SQL script, accept the output from the statement back and then manipulate it in the Shell.
Viewers will learn how to use the SELECT statement in SQL to return specific rows and columns, with various degrees of sorting and limits in place.

744 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

15 Experts available now in Live!

Get 1:1 Help Now