Oracle syntax for Last four business workings days

Hi Experts

Can anyone help with the PL/SQL syntax to show dates that are within the last four business days on a where clause.

Many thanks!
MrDavidThornAsked:
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Guy Hengel [angelIII / a3]Billing EngineerCommented:
as business days would vary depending on the business, country etc, the only real solution is to use a calendar table which, for each date, indicates if it is a business day (for you) or not.
starting from there (http://www.experts-exchange.com/Database/MS-SQL-Server/A_12267-Date-Fun-Part-One-Build-your-own-SQL-calendar-table-to-perform-complex-date-expressions.html), you would query like this:
with data as ( select PKDate , row_number() over ( order by PKDate  desc) rn from days  where PKDate  < trunc(sysdate) and is_workday = 1 ) select * from data where rn <= 4 

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this is it about what you need to do, in short
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MrDavidThornAuthor Commented:
Well the Business week is Monday to Friday, so I want to avoid Saturday / Sunday
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Guy Hengel [angelIII / a3]Billing EngineerCommented:
is this the case for all your weeks? or will the official holidays not be skipped also?
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johnsoneSenior Oracle DBACommented:
Assuming that you don't want to account for holidays, and only care about Saturday/Sunday, then this should work.
SELECT d 
FROM   (SELECT d 
        FROM   (SELECT Trunc(SYSDATE) - LEVEL + 1 d 
                FROM   dual 
                CONNECT BY LEVEL <= 7) 
        WHERE  Trim(To_char(d, 'Day')) NOT IN ( 'Saturday', 'Sunday' ) 
        ORDER  BY d) 
WHERE  ROWNUM <= 4; 

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Guy Hengel [angelIII / a3]Billing EngineerCommented:
ORDER  BY d)
should that not be :
ORDER  BY d desc)
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johnsoneSenior Oracle DBACommented:
Yes, I somehow missed that in the cut and paste.
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awking00Information Technology SpecialistCommented:
Just to be clear, if today were Tuesday, you want a where clause that would select records with a date of yesterday, last Friday, Thursday, or Wednesday?
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MikeOM_DBACommented:
Or this (just subtract the holidays):
(  GREATEST ( NEXT_DAY ( v_start_date, 'MON') - v_start_date - 2, 0)
          + ((NEXT_DAY ( v_end_date, 'MON') - NEXT_DAY ( v_start_date, 'MON'))  / 7)  * 5)
          -  (GREATEST ( NEXT_DAY ( v_end_date, 'MON') - v_end_date - 3, 0))
          - Holidays

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:p
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