MySql Query rows for this year

I have a query that i need to get only the rows that are for the current year.

The column that has the unix time is referrals.entered

here is the current query:

SELECT referrals.*, to_person.fname as to_fname, to_person.lname as to_lname, from_person.fname as from_fname, from_person.lname as from_lname FROM referrals LEFT JOIN person as from_person ON (from_person.ID = referrals.from_ID) LEFT JOIN person as to_person ON (to_person.ID = referrals.to_ID) LEFT JOIN chapter_relation as from_relation ON (from_person.ID = from_relation.person_ID) LEFT JOIN chapter_relation as to_relation ON (to_person.ID = to_relation.person_ID) WHERE from_relation.chapter_ID = to_relation.chapter_ID AND from_relation.chapter_ID = '$chapterid' ORDER BY referrals.entered DESC
jporter80Asked:
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GaryCommented:
There is nothing in your query where you filter on year so

WHERE
....
YEAR(referrals.entered)=2014
....

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GaryCommented:
Or did you mean for this to be a generic sql for whatever the current year is?

WHERE
....
YEAR(referrals.entered)=YEAR(CURDATE())
....

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jporter80Author Commented:
Well maybe i answered my own question... but i just did it this way unless you think it could be better:

$currentyear = date('Y');
$startyear = strtotime("01 January ".$currentyear);
$endyear = strtotime("31 December ".$currentyear);

$numberreferrals = mysqli_query($mysqliglobal,"SELECT referrals.*, to_person.fname as to_fname, to_person.lname as to_lname, from_person.fname as from_fname, from_person.lname as from_lname FROM referrals LEFT JOIN person as from_person ON (from_person.ID = referrals.from_ID) LEFT JOIN person as to_person ON (to_person.ID = referrals.to_ID) LEFT JOIN chapter_relation as from_relation ON (from_person.ID = from_relation.person_ID) LEFT JOIN chapter_relation as to_relation ON (to_person.ID = to_relation.person_ID) WHERE from_relation.chapter_ID = to_relation.chapter_ID AND from_relation.chapter_ID = '$chapterid' AND referrals.entered > $startyear AND referrals.entered < $endyear ORDER BY referrals.entered DESC");
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GaryCommented:
I think it's easier going the sql route, and just pass in the year from php using
$year = date("Y");
...
WHERE
....
YEAR(referrals.entered)=$year
....

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Doing a date > and date < is just wasted code.
Plus the way you have it it would be
year > 2014 and year < 2014 = nothing
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jporter80Author Commented:
im using unix time so the variables declared before query are getting unix time of the beginning of the current year and the end of the current year. Now im querying everything in between with > or <
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GaryCommented:
Ahh true - thought you were querying against the year, still it would be easier and less code to just query on the year as exampled here http:#a40512263

edit.
Your code is still > than the 1st of Jan and < 31st Dec which means the 2nd Jan til the 30th Dec
Should >= and <=
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Brian TaoSenior Business Solutions ConsultantCommented:
Just a reminder: use >= and <= otherwise you'll miss the data from the first and the last day of the year!
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jporter80Author Commented:
ahhh.. thanks for the catch
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