troubleshooting Question

Single row for Count(column is NULL), Count(all rows)

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Jim HornFlag for United States of America asked on
Microsoft SQL ServerMicrosoft SQL Server 2008
10 Comments4 Solutions156 ViewsLast Modified:
Hi all

Does anyone have some quick and dirty (copyright jimpen) T-SQL to return a set with a single row that contains a count of all rows where a specific value is NULL (say column_name), and a count of the rows in the entire table (say table_name)?

I've put together the below CTE, which works fine, but it seems like there's a more elegant way to do this that I'm not grasping.

Thanks in advance.

WITH m as (
	SELECT 'Account' as label, COUNT(id) as row_count_column_name_missing
	FROM table_name
	WHERE column_name IS NULL)
, a as (	
	SELECT 'Account' as label, COUNT(id) as row_count_all
	FROM table_name) 
	CAST(m.row_count_column_name_missing / CAST(row_count_all as numeric(19,4)) * 100 as numeric(5,2)) as pct_missing
	JOIN a ON m.label = a.label
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