Why Experts Exchange?

Experts Exchange always has the answer, or at the least points me in the correct direction! It is like having another employee that is extremely experienced.

Jim Murphy
Programmer at Smart IT Solutions

When asked, what has been your best career decision?

Deciding to stick with EE.

Mohamed Asif
Technical Department Head

Being involved with EE helped me to grow personally and professionally.

Carl Webster
CTP, Sr Infrastructure Consultant
Ask ANY Question

Connect with Certified Experts to gain insight and support on specific technology challenges including:

Professional Opinions
Ask a Question
Did You Know?

We've partnered with two important charities to provide clean water and computer science education to those who need it most. READ MORE

troubleshooting Question

Single row for Count(column is NULL), Count(all rows)

Avatar of Jim Horn
Jim HornFlag for United States of America asked on
Microsoft SQL ServerMicrosoft SQL Server 2008
10 Comments1 Solution156 ViewsLast Modified:
Hi all

Does anyone have some quick and dirty (copyright jimpen) T-SQL to return a set with a single row that contains a count of all rows where a specific value is NULL (say column_name), and a count of the rows in the entire table (say table_name)?

I've put together the below CTE, which works fine, but it seems like there's a more elegant way to do this that I'm not grasping.

Thanks in advance.

WITH m as (
	SELECT 'Account' as label, COUNT(id) as row_count_column_name_missing
	FROM table_name
	WHERE column_name IS NULL)
, a as (	
	SELECT 'Account' as label, COUNT(id) as row_count_all
	FROM table_name) 
	CAST(m.row_count_column_name_missing / CAST(row_count_all as numeric(19,4)) * 100 as numeric(5,2)) as pct_missing
	JOIN a ON m.label = a.label