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How to show a form from a button in C# 2012?
Posted on 2014-12-23
The following code should work, but instead I get an error for the line:
frmInvoice.Show;
Error: Only assignment, call, increment, decrement, await, and new object expressions can be used as a statement.
What am I doing wrong?
frmInvoice.Show;
Error: Only assignment, call, increment, decrement, await, and new object expressions can be used as a statement.
What am I doing wrong?
private void button1_Click(object sender, EventArgs e)
{
FormInvoice frmInvoice = new FormInvoice();
frmInvoice.Show;
}
[X]
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4 Comments
Show is a method and should be called as such
Show();
http://msdn.microsoft.com/en-us/library/system.windows.forms.form.show%28v=vs.110%29.aspx
Show();
private void button1_Click(object sender, EventArgs e)
{
FormInvoice frmInvoice = new FormInvoice();
frmInvoice.Show();
}
http://msdn.microsoft.com/en-us/library/system.windows.forms.form.show%28v=vs.110%29.aspx
Active 2 days ago
*No Points*
You also have an additional method called ShowDialog. The difference is that Show does not block your code and allows for the user to move between the parent/child windows at will. Show is perfect for scenarios where the parent/child are not codependent.
In cases where the parent is launching a child window because the child is responsible for additional logic and/or information that will be displayed later on the parent, that is when ShowDialog is beneficial.
Show vs. ShowDialog
-saige-
You also have an additional method called ShowDialog. The difference is that Show does not block your code and allows for the user to move between the parent/child windows at will. Show is perfect for scenarios where the parent/child are not codependent.
In cases where the parent is launching a child window because the child is responsible for additional logic and/or information that will be displayed later on the parent, that is when ShowDialog is beneficial.
Show vs. ShowDialog
-saige-
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