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Oracle MAX function

Posted on 2014-12-29
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Last Modified: 2014-12-29
-- OK this works fine if I want to extract maxmum value from
-- group and by taht I mean that there is data such as departments and tehre are
-- veriuos salaries in those departments so MAX extracts the biggest one from each group
-- in this case DEPARTMENT_ID and that's it
SELECT DEPARTMENT_ID, MAX(SALARY) 
FROM EMPLOYEES 
GROUP BY DEPARTMENT_ID;

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-- But what if I want to find single individual(s) with highest sallary?
-- and to dispaly his/her/their name and ID?
-- WITHOUT using JOIN just with selects or nested selects?

-- With following query MAX function displays ALL employess wityh their salaries

SELECT EMPLOYEE_ID, FIRST_NAME, LAST_NAME,  MAX(SALARY) 
FROM EMPLOYEES 
GROUP BY EMPLOYEE_ID, FIRST_NAME, LAST_NAME;

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Screen-Shot-12-29-14-at-08.23-PM.PNG
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Question by:KPax
2 Comments
 
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Accepted Solution

by:
Geert Gruwez earned 500 total points
ID: 40522337
group by  and a max
the max is done per items in the group by

you designated the group by as employee_id, ...
the employee_id is unique (primary key), so the group by works on 1 element every time

the max wage of the employee itself, is the wage of the employee

the single individual (or equals) is the max salary over the total group

select max(salary) from employees

and then use that to get the highest roller :

select * from employees where salary = (select max(salary) from employees)

you can alternatively add a highest salary as extra column

select e.*, max(salary) over (order by employee_id) as max_salary
from employees e
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Author Closing Comment

by:KPax
ID: 40522362
Thank you, that's the answer I was looking for.
Although I am not quite sure what was this supposed to do
select e.*, max(salary) over (order by employee_id) as max_salary
from employees e

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this

select max(salary) from employees

-- and then use that to get the highest roller :

select * from employees where salary = (select max(salary) from employees)

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makes perfect sense to me and it works!
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