blackcatkempo
asked on
SQL Query Assistance (Disinct Count)
Hello, I am looking for assistance creating a query. I need to count the number of distinct records based on the name of the record and rated by category. See sample below.
SELECT DISTINCT COUNT(*) AS Count, [Category]
FROM [table name]
WHERE NAME LIKE [Name]
GROUP BY [Category]
I want to list the following columns
Count| Name| Category
Thank you
SELECT DISTINCT COUNT(*) AS Count, [Category]
FROM [table name]
WHERE NAME LIKE [Name]
GROUP BY [Category]
I want to list the following columns
Count| Name| Category
Thank you
It might help if you give some sample data and sample expected output,
ASKER
Attached is sample data. I need to sort through thousands of records similar. Key columns Category and Name. I want a count of a distinct name based on category.
Nothing attached.
COUNT can use DISTINCT inside it, which is really useful:
SELECT COUNT(DISTINCT Name) AS Count_Distinct_Names, [Category]
FROM [table name]
WHERE NAME LIKE [Name] --??
GROUP BY [Category]
SELECT COUNT(DISTINCT Name) AS Count_Distinct_Names, [Category]
FROM [table name]
WHERE NAME LIKE [Name] --??
GROUP BY [Category]
ASKER
ASKER
I think I need to clarify. Using the sample-data.csv. I would like to report the total number of distinct records (name) that meet a specific criteria (category).
SELECT DISTINCT COUNT(*) AS Count, Risk
FROM [tablename]
WHERE NAME LIKE 'Microsoft XML Parser%'
GROUP BY Category
ORDER BY Category ASC
Results in (columns in pipes) ---- I want another column with the name, which is related/assigned a category.
Count|Category
32| High
Need to result with following columns.
Count of Distinct Name | Name | Category
Please let me know if I need to provide further detail. Thank you.
SELECT DISTINCT COUNT(*) AS Count, Risk
FROM [tablename]
WHERE NAME LIKE 'Microsoft XML Parser%'
GROUP BY Category
ORDER BY Category ASC
Results in (columns in pipes) ---- I want another column with the name, which is related/assigned a category.
Count|Category
32| High
Need to result with following columns.
Count of Distinct Name | Name | Category
Please let me know if I need to provide further detail. Thank you.
Without a sample data set leading to a sample result, I cannot help you.
Your attached sample data does not lead to a result of 32, High, and therefore I would still be guessing as to what you want.
Your attached sample data does not lead to a result of 32, High, and therefore I would still be guessing as to what you want.
ASKER
Attached is a sanitized version for sample data. Using this file, I would like to see the following columns in a query displaying the number of distinct occurrences of the name record.
Count of Distinct Name | Name | Risk
Count of distinct name - the number of instances of the name
Name - the name of the risk
Risk - the risk level
Does this help?
Count of Distinct Name | Name | Risk
Count of distinct name - the number of instances of the name
Name - the name of the risk
Risk - the risk level
Does this help?
ASKER
Select [Name], Count(Distinct [Name]) as CountOfDistinctName, Risk
From [tablename]
Group by [Name], Risk
From what you have described, the only thing wrong with your previous example was the placement of the word "Distinct".
From [tablename]
Group by [Name], Risk
From what you have described, the only thing wrong with your previous example was the placement of the word "Distinct".
Note that it is very similar to Scott's solution.
ASKER
Thank you for the query. I would like to see the number of distinct occurrences (risks) displayed for each name . The script your provided only displays a "1" for each row (name). I apologize if i am not explaining properly.
Then
Select [Name], Count(Distinct [Risk]) as CountOfDistinctName, Risk
From [tablename]
Group by [Name], Risk
Select [Name], Count(Distinct [Risk]) as CountOfDistinctName, Risk
From [tablename]
Group by [Name], Risk
ASKER
Sorry that query provided the same result - only displays a "1". I have confirmed there are more then one instance per name using a separate individual query.
Select [Name],
(select Count(Distinct [Risk])
From [tablename] as U
Where T.[Name] = U.[Name]) as CountOfDistinctName,
Risk
From [tablename] as T
Group by [Name], Risk
(select Count(Distinct [Risk])
From [tablename] as U
Where T.[Name] = U.[Name]) as CountOfDistinctName,
Risk
From [tablename] as T
Group by [Name], Risk
ASKER
Same result.
Try this:
Select [Name],
(select Count([Risk])
From [tablename] as U
Where T.[Name] = U.[Name]) as CountOfDistinctName,
Risk
From [tablename] as T
Group by [Name], Risk
This gives this result:
Adobe Reader Detection 1 None
Adobe Reader Enabled in Browser (Internet Explorer) 1 None
Antivirus Software Check 1 None
BIOS Version (WMI) 1 None
Citrix Online Plug-in Installed 1 None
Citrix Receiver / Online Plug-in Remote Code Execution (CTX134681) 1 High
Common Platform Enumeration (CPE) 4 None
Computer Manufacturer Information (WMI) 1 None
DCE Services Enumeration 4 None
Adobe Reader Detection 1 None
Adobe Reader Enabled in Browser (Internet Explorer) 1 None
Antivirus Software Check 1 None
BIOS Version (WMI) 1 None
Citrix Online Plug-in Installed 1 None
Citrix Receiver / Online Plug-in Remote Code Execution (CTX134681) 1 High
Common Platform Enumeration (CPE) 4 None
Computer Manufacturer Information (WMI) 1 None
DCE Services Enumeration 4 None
ASKER
Thanks Phillip, can I also use Count(Distinct Host)? The code you provided works great, however the data table contains multiple risks for the same host. I just want to count the single risk by host.
ASKER CERTIFIED SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
ASKER
Thank you!
ASKER
Hi Phillip,
One more follow up question regarding this query you crafted for me. For some reason I can not use the WHERE IN clause for the column risk. I am specifically looking for the number of Critical, High, etc. The results provide the number of all rows with a risk. See query below. Thank you.
Select Distinct [Host], Risk,
(select Count (Distinct [Name])
From [tablename] as U
Where T.[Host] = U.[Host]) as CountOfDistinctRisk
From [tablename] as T
WHERE Risk IN ('Critical','High')
Group by [Host], Name, Risk
ORDER by [CountofDistinctRisk] DESC
One more follow up question regarding this query you crafted for me. For some reason I can not use the WHERE IN clause for the column risk. I am specifically looking for the number of Critical, High, etc. The results provide the number of all rows with a risk. See query below. Thank you.
Select Distinct [Host], Risk,
(select Count (Distinct [Name])
From [tablename] as U
Where T.[Host] = U.[Host]) as CountOfDistinctRisk
From [tablename] as T
WHERE Risk IN ('Critical','High')
Group by [Host], Name, Risk
ORDER by [CountofDistinctRisk] DESC
Shouldn't it be inside the brackets?
Select Distinct [Host], Risk,
(select Count (Distinct [Name])
From [tablename] as U
Where T.[Host] = U.[Host] AND Risk IN ('Critical','High')) as CountOfDistinctRisk
From [tablename] as T
Group by [Host], Name, Risk
ORDER by [CountofDistinctRisk] DESC
ASKER
Having the AND statement inside of the sub query provides different results that are not accurate. I actually do no know what it is reporting/resulting, essentially the countofdistinctrisk column produces a number that is not made up the total risks aggregate or something else. We need the count of total number of critical, high, per hostname.
Sounds like this would work, if all you want is a filtered list:
I wouldn't understand why it wouldn't work.
Select [Name],
(select Count([Risk])
From [tablename] as U
Where T.[Name] = U.[Name]) as CountOfDistinctName,
Risk
From [tablename] as T
WHERE Risk IN ('Critical','High')
Group by [Name], Risk
I wouldn't understand why it wouldn't work.