How to pass an array to a shell script?

Hello,
I have a shell script which accepts 2 variables, (example below of how i execute it), how can i auotomate the script such that i can pass 10 sets of variables? (10 lines of 2 variable each) so that I dont have to execute the script 10 times?
Thank you,
shobha.
Rao_SAsked:
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TintinConnect With a Mentor Commented:
expanding on ozo's last suggestion, I'm guessing you wouldn't want to manually type out 80 pairs of parameters, so I'm assuming you'd have them in a file, in which case, you can do:

while read p f; do
      # now process that pair of values                                                                                                                       
      create_oem_user_emcli -p $p -f  $f
done </path/to/file-with-parameters

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simon3270Connect With a Mentor Commented:
One option would be to pass all of the values one after the other, as in

   Script.sh a1 a2 b1 b2 c1 c2

Then in the script

    while [ "$1" != "" ]; do
        Val1=$1
        Val2=$2
        # now process that pair of values

       # now remove the first 2 parms from list
       shift 2
    done
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Rao_SAuthor Commented:
This is how i run it now...

$create_oem_user_emcli -p PPTEST -f TESTING

i need to pass about 80 sets of -p and -f...
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ozoConnect With a Mentor Commented:
Applying  simon3270's suggestion to how you run it now:

while [ $# -ge 2 ]; do
        # now process that pair of values
        create_oem_user_emcli -p $1 -f  $2

       # now remove the first 2 parms from list
       shift 2
done


If you prefer to send in lines of 2 variable each, you might use:

while read p f; do
      # now process that pair of values                                                                                                                      
      create_oem_user_emcli -p $p -f  $f
done
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Rao_SAuthor Commented:
Thank you very much, the script worked!
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