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SQL Query to display last row inserted

I have a SQL 2005 Database. I'm looking for a relatively simple query to do the following. This is a very simplified example of the table. There are obviously more than two unique SystemNumbers.

TableName is Data

DataID         SystemNumber       TimeStamp
27765178    8001                          11:00 AM
27765179    8001                          11:02 AM
....
2777192      8555                          10:32 AM
2777193      8555                          10:37 AM

I need a query that can be run that will display the results like so:

DataID       SystemNumber       TimeStamp
27765178  8001                          11:02 AM
2777193    8555                          10:37 AM

So the most recent TImeStamp for each unique SystemNumber.

Any suggestions on how I can do this?

Eventually I will be using this on some SQL 2000 (I know) servers too, and putting into SQL Server Reporting
0
KThrace
Asked:
KThrace
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1 Solution
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
>So the most recent TImeStamp for each unique SystemNumber.
Give this a whirl.
Subquery gets the max time stamp for a given SystemNumber
Main query gets all rows in Data that match the above two values.
SELECT d.DataID, d.SystemNumber, dm.time_max as TimeStamp
FROM Data d
   JOIN (SELECT SystemNumber, Max(TimeStamp) as time_max 
         FROM Data
         GROUP BY SystemNumber) dm ON d.SystemNumber = dm.SystemNumber AND d.TimeStamp = dm.time_max
ORDER BY d.SystemNumber

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For more examples see SQL Server GROUP BY Solutions,
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KThraceAuthor Commented:
Beautiful! Works on 2005 AND 2000! I'll accept as a solution but as a follow up...

...for whatever reason in the table I have different DataID but same SystemNumber and EXACTLY same TimeStamp - so the result actually brings back two rows for each unique systemnumber. Is there a quick and easy way to add a statement such that:

If SystemNumber AND TimeStamp are the same return only one result
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
How would you determine which 'one' to display?  Min(DataID), Max(DataID), I don't care just pick one, ...
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KThraceAuthor Commented:
Max(DataID)
0
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Try this then.
SELECT Max(d.DataID), d.SystemNumber, dm.time_max as TimeStamp
FROM Data d
   JOIN (SELECT SystemNumber, Max(TimeStamp) as time_max 
         FROM Data
         GROUP BY SystemNumber) dm ON d.SystemNumber = dm.SystemNumber AND d.TimeStamp = dm.time_max
GROUP BY d.SystemNumber, dm.time_max
ORDER BY d.SystemNumber

Open in new window

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KThraceAuthor Commented:
Jim, it's perfect!

Thank you so much!
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KThraceAuthor Commented:
Perfect and elegant!
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Thanks for the grade.  Good luck with your project.  -Jim
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