SQL Max Group By to get the second largest value

Hi there,

I have the below query to obtain the largest value using group by to get the largest size_min value for each model type. However I would like to get the second largest value for size_min using the same premise of which groups by model_type gets the max size_min but obtaining the actual value for price_1 and price_2 like below.

I may have confused you there,  but I have also attached a spreadsheet which better illustrates what I would like to do:

SELECT        tt.model_ID, tt.model_type, tt.size_min, tt.model_price_1, tt.model_price_2
FROM            dbo.Model AS tt INNER JOIN
                             (SELECT        model_type, MAX(size_min) AS MaxMin
                               FROM            dbo.Model E1
                               GROUP BY model_type) AS groupedtt ON tt.model_type = groupedtt.model_type AND tt.size_min = groupedtt.MaxMin;

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I  hope this makes sense and thank you for your help in advance.
Table-structure-and-results.xls
databarracksAsked:
Who is Participating?
 
Guy Hengel [angelIII / a3]Connect With a Mentor Billing EngineerCommented:
sorry, I forgot the alias for the subquery
select * from (
SELECT        tt.model_ID, tt.model_type, tt.size_min, tt.model_price_1, tt.model_price_2
  , row_number() over (partition by tt.model_ID, tt.model_type  order by  tt.size_min desc ) rn
 , count(*) over ( partition by tt.model_ID, tt.model_type  ) cnt
FROM            dbo.Model AS tt
) sq
where rn = 2 or cnt = 1
                                          

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Guy Hengel [angelIII / a3]Billing EngineerCommented:
to get the Nth number in an order you can use ROW_NUMBER() function in a subquery, similarly to what I suggest in this article:http://www.experts-exchange.com/Database/Miscellaneous/A_3203-DISTINCT-vs-GROUP-BY-and-why-does-it-not-work-for-my-query.html

select * from (
SELECT        tt.model_ID, tt.model_type, tt.size_min, tt.model_price_1, tt.model_price_2
  , row_number() over (partition by tt.model_ID, tt.model_type  order by  tt.size_min desc ) rn
FROM            dbo.Model AS tt
)
where rn = 2

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the issue that I see is that if there is only 1 single record for a "partition", it will not return anything...
in that case, we can add something like this to make sure we still get at least 1 row


select * from (
SELECT        tt.model_ID, tt.model_type, tt.size_min, tt.model_price_1, tt.model_price_2
  , row_number() over (partition by tt.model_ID, tt.model_type  order by  tt.size_min desc ) rn
 , count(*) over ( partition by tt.model_ID, tt.model_type  ) cnt
FROM            dbo.Model AS tt
)
where rn = 2 or cnt = 1

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databarracksAuthor Commented:
Hi Guy,

I am getting incorrect syntax here FROM  dbo.Model AS tt)
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databarracksAuthor Commented:
Hey Guy,

That fixed the error but I am getting all the rows and not 3 rows as per my spreadsheet?
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databarracksAuthor Commented:
When I run the query all rn and cnt values are 1???
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databarracksAuthor Commented:
Ahhhh alas It was because of the id column inside the partition statement. Seeing as they are unique it makes sense. Removed this from the query and it works:)
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databarracksAuthor Commented:
Many thanks for your help on this Guy, you have been tremendous
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databarracksAuthor Commented:
Excellent, responsive and also added extra information which is helpful. Brilliant stuff
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