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Is there a LIKE function in Excel

Posted on 2015-01-13
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Last Modified: 2015-02-11
I have three thousand rows. In one column there is a field that in some instances contains the word "mattress". I want to see how many instances there are.
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Question by:CMChalcraft
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Expert Comment

by:Patrick Matthews
ID: 40546752
Use COUNTIF.

For example:

=COUNTIF(A1:A100,"mattress") to see how many cells have ONLY the word "mattress" as their values

=COUNTIF(A1:A100,"*mattress*") to see how many cells have the word "mattress" within their values, as well as potentially some other text
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Accepted Solution

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Phillip Burton earned 500 total points
ID: 40546756
find or search can find a value inside a word, e.g.

=if(iserror(SEARCH("mattress",A1)),"No","Yes")

If you want to count multiple instances, then you can use the array formula

=SUM(IF(ISERROR(SEARCH("mattress",A:A)),0,1))

and press Ctrl+Shift+Enter instead of pressing Enter (change A:A to your range).

Alternatively, do a filter on that column, and the number of instances will be in the status bar at the bottom.
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Author Comment

by:CMChalcraft
ID: 40546779
Thank you. I have used =if(iserror(SEARCH("mattress",A1)),"No","Yes").

This is a spreadsheet a colleague has created and he wants to enter 1 or 0 for each matched instance. I have amended the formula to do this.

Very prompt!

Regards

Chris
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Expert Comment

by:Patrick Matthews
ID: 40546793
COUNTIF does the exact same thing, without having to resort to an array formula.  Did you even try it?
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Expert Comment

by:Glenn Ray
ID: 40552573
^ Best solution (COUNTIF).  No helper column needed; inserts the total in one cell; ultimately faster than having several thousand individual formulas returning 1 or 0.
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Expert Comment

by:Martin Liss
ID: 40602754
This question has been classified as abandoned and is closed as part of the Cleanup Program. See the recommendation for more details.
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