asked on

removing the character from attribute values in xml through xslt

i have the below xml , need to change it to the result xml mentioned below, i have taken help from the forum members for the same earlier and have the following xslt(modified a bit to include additional tags), it is working fine to remove the the characters "\b." and "\b0". from Section[@type='Income']/Summary/Amount/@Name but not from
"Section[@type='Income']/Summary/Persons/Person/@Name , could you please let me know where am i going wrong on this ..? i need to change the characters in this particular "Section[@type='Income']" as i have similar tags with diff attribute names hat i need to keep it as is.

========xslt=========

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()" />
</xsl:copy>
</xsl:template>

<xsl:template match="Correspondance/Ledger/Section[@type='Income']">
<Income><xsl:apply-templates select="@*|node()" /></Income>
</xsl:template>
<xsl:template match="Correspondance/Ledger/Section[@type='Expense']">
<Expense><xsl:apply-templates select="@*|node()" /></Expense>
</xsl:template>
<xsl:template match="Correspondance/Ledger/Section[@type='Deduction']">
<Deduction><xsl:apply-templates select="@*|node()" /></Deduction>
</xsl:template>

<xsl:template match="Section[@type='Income']/Summary/Amount/@Name">
<xsl:attribute name="Name">
<xsl:call-template name="strip-name">
<xsl:with-param name="str" select="."></xsl:with-param>
</xsl:call-template>
</xsl:attribute>
</xsl:template>

<xsl:template name="strip-name">
<xsl:param name="str"/>
<xsl:value-of select="substring-before(substring-after($str, '\b.'), '\b0.')"/>
</xsl:template>

<xsl:template match="Section[@type='Income']/Summary/Persons/Person/@Name">
<xsl:attribute name="Name">
<xsl:call-template name="strip-name-inc">
<xsl:with-param name="str" select="."></xsl:with-param>
</xsl:call-template>
</xsl:attribute>
</xsl:template>

<xsl:template name="strip-name-inc">
<xsl:param name="str1"/>
<xsl:value-of select="substring-before(substring-after($str1, '\b.'), '\b0.')"/>
</xsl:template>

</xsl:stylesheet>
=========================================================================

========================
current xml
==========================

<Section type="Expense">
<SubDetails>
<Sub>
<HeaderLogo>d:\Apps\MCI\PRD\Adobe\Corr\Logo\icon_elig_bills.gif</HeaderLogo>
<Header>Expenses</Header>
<AssetSubHeader>Who has expenses?</AssetSubHeader>
<Caption>Who has expenses?</Caption>
<TotalText>Total expenses</TotalText>
<Month1>12/2014</Month1>
<Month2>01/2015</Month2>
</Sub>
</SubDetails>
<Persons>
<Person>
<Name>\b.GILBERTO\b0.</Name>
<Source>Goods, supplies and material cost</Source>
</Person>
<Person>
<Name>\b.GILBERTO\b0.</Name>
<Source>Other</Source>
</Person>
</Persons>
<Summary>
<Amount Name="\b.GILBERTO\b0." Source="Goods, supplies and material cost" Month="12/2014">29.17</Amount>
<Amount Name="\b.GILBERTO\b0." Source="Other" Month="12/2014">8.33</Amount>
<Amount Name="\b.GILBERTO\b0." Source="Goods, supplies and material cost" Month="01/2015">29.17</Amount>
<Amount Name="\b.GILBERTO\b0." Source="Other" Month="01/2015">8.33</Amount>
</Summary>
</Section>

need to remove the "\b." and "\b0." from the <Section type="Expense".

the result xml needs to be

<Section type="Expense">
<SubDetails>
<Sub>
<HeaderLogo>d:\Apps\MCI\PRD\Adobe\Corr\Logo\icon_elig_bills.gif</HeaderLogo>
<Header>Expenses</Header>
<AssetSubHeader>Who has expenses?</AssetSubHeader>
<Caption>Who has expenses?</Caption>
<TotalText>Total expenses</TotalText>
<Month1>12/2014</Month1>
<Month2>01/2015</Month2>
</Sub>
</SubDetails>
<Persons>
<Person>
<Name>GILBERTO</Name>
<Source>Goods</Source>
</Person>
<Person>
<Name>GILBERTO</Name>
<Source>Other</Source>
</Person>
</Persons>
<Summary>
<Amount Name="GILBERTO" Source="Goods" Month="12/2014">29.17</Amount>
<Amount Name="GILBERTO" Source="Other" Month="12/2014">8.33</Amount>
<Amount Name="GILBERTO" Source="Goods" Month="01/2015">29.17</Amount>
<Amount Name="GILBERTO" Source="Other" Month="01/2015">8.33</Amount>
</Summary>
</Section>

Thanks in advance

ASKER CERTIFIED SOLUTION

Gertone (Geert Bormans)

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sri1209

ASKER

Thank you for trying to help me out here, but being new to this and not able to understand how to make it work in a slightly different requirement , i would like to know and learn how can i remove the "\b." and \b0." from the
"Section[@type='Income']/Summary/Persons/Person/Name

the following xslt works fine to remove the "\b." and "\b0." from Section[@type='Income']/Summary/Amount/@Name
current xslt:

========xslt=========

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()" />
</xsl:copy>
</xsl:template>

<xsl:template match="Correspondance/Ledger/Section[@type='Income']">
<Income><xsl:apply-templates select="@*|node()" /></Income>
</xsl:template>
<xsl:template match="Correspondance/Ledger/Section[@type='Expense']">
<Expense><xsl:apply-templates select="@*|node()" /></Expense>
</xsl:template>
<xsl:template match="Correspondance/Ledger/Section[@type='Deduction']">
<Deduction><xsl:apply-templates select="@*|node()" /></Deduction>
</xsl:template>

<xsl:template match="Section[@type='Income']/Summary/Amount/@Name">
<xsl:attribute name="Name">
<xsl:call-template name="strip-name">
<xsl:with-param name="str" select="."></xsl:with-param>
</xsl:call-template>
</xsl:attribute>
</xsl:template>
-----this part of the xslt does not work it removes the whole <Name >tag from xml not from the value of the <Name>---
<xsl:template match="Section[@type='Income']/Summary/Persons/Person/Name">
<xsl:attribute name="Name">
<xsl:call-template name="strip-name-inc">
<xsl:with-param name="str" select="."></xsl:with-param>
</xsl:call-template>
</xsl:attribute>
</xsl:template>

<xsl:template name="strip-name">
<xsl:param name="str"/>
<xsl:value-of select="substring-before(substring-after($str, '\b.'), '\b0.')"/>
</xsl:template>

</xsl:stylesheet>

Thank you .

sri1209

ASKER

figured it out now , thank you for the help.

Gertone (Geert Bormans)

welcome