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# Excel -- Index Match array giving incorrect result

Posted on 2015-01-22
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Greetings,

I have a formula that is intended to retrieve a list of IP addresses from a sheet named ip. The ip sheet stores the ip addresses in the second column (B). Whenever I enter the name of the server into A2 on the lookup sheet it gives me the IP address that falls one cell below the intended result.

``````=IF(ISERROR(INDEX(ip!\$A\$2:\$B\$241,SMALL(IF(ip!\$A\$1:\$A\$241=\$A\$2,ROW(ip!\$A\$2:\$A\$242)),ROW(1:1)),2)),"",INDEX(ip!\$A\$2:\$B\$236,SMALL(IF(ip!\$A\$2:\$A\$242=\$A\$2,ROW(ip!\$A\$2:\$A\$242)),ROW(1:1)),2))
``````

If you have any questions let me know.

NeptuneIT
0
Question by:neptuneit

LVL 25

Expert Comment

ID: 40564414
Diffcult to say, without seeing the worksheet.

but in the meanwhile, can you try

=IF(ISERROR(INDEX(ip!\$A\$2:\$B\$241,SMALL(IF(ip!\$A\$1:\$A\$241=\$A\$2,ROWS(ip!\$A\$2:\$A\$242)),ROW(1:1)),2)),"",INDEX(ip!\$A\$2:\$B\$236,SMALL(IF(ip!\$A\$2:\$A\$242=\$A\$2,ROWS(ip!\$A\$2:\$A\$242)),ROW(1:1)),2))
0

LVL 31

Expert Comment

ID: 40564537
I believe you need to adjust all of the ranges referred to from the ip sheet to starting at the same row, ie ip!\$A\$2, you have some starting at ip!\$A\$1.

I don't think the finishing rows being different is an issue in this case but worth changing those to the same as well.

Thanks
Rob H
0

LVL 31

Expert Comment

ID: 40564549
As an aside, you can probably shrink the formula using IFERROR(..) rather than IF(ISERROR(..)).

Syntax:

=IFERROR(Formula,ErrorResult)

In your case, (I have adjusted for all same ranges as mentioned above, but check the brackets!!):

=IFERROR(INDEX(ip!\$A\$2:\$B\$242,SMALL(IF(ip!\$A\$2:\$A\$242=\$A\$2,ROWS(ip!\$A\$2:\$A\$242)),ROW(1:1)),2)),"")

Thanks
Rob H
0

LVL 1

Author Comment

ID: 40564590
ip!\$A\$1 is the header, is it still required?
0

LVL 1

Author Comment

ID: 40564620
Also Rob, changing the \$A\$2 to \$A\$1 generates an empty result
0

LVL 31

Expert Comment

ID: 40564641
I was suggesting the other way, make all ranges start at A2.
0

LVL 50

Accepted Solution

barry houdini earned 500 total points
ID: 40564778
>=IFERROR(INDEX(ip!\$A\$2:\$B\$242,SMALL(IF(ip!\$A\$2:\$A\$242=\$A\$2,ROWS(ip!\$A\$2:\$A\$242)),ROW(1:1)),2)),"")

You can't have ROWS in that part, Rob

Try this version, assuming you enter the formula in D2 and copy down

=IFERROR(INDEX(ip!\$A\$2:\$B\$242,SMALL(IF(ip!\$A\$2:\$A\$242=\$A\$2,ROW(ip!\$A\$2:\$A\$242)-ROW(ip!\$A\$2)+1),ROWS(D\$2:D2)),2),"")

confirmed with CTRL+SHIFT+ENTER

regards, barry
0

LVL 45

Expert Comment

ID: 40628866
I've requested that this question be deleted for the following reason:

Not enough information to confirm an answer.
0

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