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Rename CSV file for MS Access 2010

I'm using the code below to rename  CSV files.

On Error Resume Next
Dim csvFile As String, xFile As String, csvFolder As String
 Dim vArr() As String, j As Integer, xName As String

 csvFolder = "C:\Students\"  '<<< CHANGE to CORRECT path
 csvFile = Dir(csvFolder & "*.csv")
 While csvFile <> ""

         vArr = Split(csvFile, " ")
         For j = 0 To UBound(vArr)
             If InStr(vArr(j), "Science_MP1") Then
                 xFile = vArr(j)
                 Exit For
             End If
         Next
         xName = Mid(csvFile, InStrRev(csvFile, "("))
         xName = Replace(Replace(xName, "(", ""), ")", "")
         Debug.Print xFile & "_" & xName
         
         Name csvFolder & csvFile As csvFolder & xFile & "_" & xName
         
         csvFile = Dir()
 Wend

The code works fine when the CSV file in the following format:
Grade Sheet Report for test 05_Science_MP1 for section 5th Grade Science-5th Grade Science-002-04(M-F)(Patricia Ashley).csv and I get the following expected result:
05_Science_MP1_Patricia Ashley.csv

If change Science to Math I get an unexpected result:
_Patricia Ashley.csv
I need to adjust the code to select starting with the first number and include anything after the two underscores plus anything between the last ()
0
shieldsco
Asked:
shieldsco
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1 Solution
 
Rey Obrero (Capricorn1)Commented:
post all possible variations
this is 1. Science_MP1

what else?
0
 
Rey Obrero (Capricorn1)Commented:
better post all the file names of the .csv files
0
 
GrahamMandenoCommented:
It looks like the input format of your CSV file names is:

<Discard1><TestName><Discard2>(StudentName).csv

and the desired result is:

<TestName>_<StudentName>.csv

You are correctly extracting <StudentName> using InstrRev to find the last left-parenthesis.

The problem appears to be identifying <TestName> .  As you have discovered, you cannot search for "Science_MP1" because it doesn't work for "Math_MP1".

QUESTION:  Does the filename always begin with "Grade Sheet Report for test "?

If so, then it is easy to remove a constant string to get to the <TestName>:

Dim csvFile As String, csvFolder As String
Dim sTestName As String, sStudentName As String
Dim sNewName as String
Const cStringToDiscard =  "Grade Sheet Report for test "
  csvFolder = "C:\Students\"  '<<< CHANGE to CORRECT path
  csvFile = Dir(csvFolder & "*.csv")
  Do Until csvFile = ""
    If Left(csvFile, Len(cStringToDiscard)) = cStringToDiscard Then
      sTestName = Mid(csvFile, Len(cStringToDiscard) + 1) ' discard prefix
      sTestName = Left(sTestName, InStr(sTestName, " ") - 1)  'discard everything from first blank onward

      sStudentName = Mid(csvFile, InStrRev(csvFile, "(") + 1) ' discard everything up to and including last "("
      sStudentName = Left(sStudentName, InStr(sStudentName, ")") - 1)  ' discard everything from first ")" onward

      sNewName = sTestName & "_" & sStudentName & ".csv"
      Debug.Print sNewName
         
      Name csvFolder & csvFile As csvFolder & sNewName
         
    End If
    csvFile = Dir()
  Loop

Open in new window

Good luck!
Graham Mandeno [Access MVP 1996-2015]
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Rey Obrero (Capricorn1)Commented:
revised codes


On Error Resume Next
 Dim csvFile As String, xFile As String, csvFolder As String
  Dim vArr() As String, j As Integer, xName As String

  csvFolder = "C:\Students\"  '<<< CHANGE to CORRECT path
  csvFile = Dir(csvFolder & "*.csv")
  While csvFile <> ""

         For j = 0 To UBound(vArr)
              If InStr(vArr(j), "Science_MP1") Then
                  xFile = vArr(j)
                  Exit For
                  elseif InStr(vArr(j), "Math_MP1") Then
                  xFile = vArr(j)
                  Exit For
              End If
          Next
         xName = Mid(csvFile, InStrRev(csvFile, "("))
          xName = Replace(Replace(xName, "(", ""), ")", "")
          'Debug.Print xFile & "_" & xName
         
          Name csvFolder & csvFile As csvFolder & xFile & "_" & xName
         
          csvFile = Dir()
  Wend
0
 
shieldscoAuthor Commented:
Thanks
0
 
Rey Obrero (Capricorn1)Commented:
@shieldsco

did you try my last post?
0
 
shieldscoAuthor Commented:
Rey - the name is variable
0
 
Rey Obrero (Capricorn1)Commented:
I ask you about it and you never replied.
0
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