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SQL Query show date in and date out on table

Posted on 2015-01-29
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Last Modified: 2015-01-30
Hi I have a table at the moment as follows

Name             Date
john                01-01-2000 09:00
john                01-01-2000 11:00
john                01-01-2000 11:15
john                01-01-2000 13:00
john                01-01-2000 13:30
john                01-01-2000 17:30

What I want to do is convert this to
Name             In                                     Out                                Time In
john                01-01-2000 09:00         01-01-2000 11:00        01:30
john                01-01-2000 11:15         01-01-2000 13:00        01:45
john                01-01-2000 13:30         01-01-2000 17:30        04:00

There are loads of people and they can lots of in and outs per day, please advise on how I could do this in SQL
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Question by:taz8020
8 Comments
 
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Expert Comment

by:Vitor Montalvão
ID: 40577435
How do you know if is coming in or out? Don't exists a column with that information?
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Expert Comment

by:echobridge
ID: 40577506
Having been down this road before, I'd might suggest restructuring your table if at all possible to record this information in the in/out format you're looking for. Makes it a lot easier when you get issues like missing information. In my situation it was people logging into a time clock, so missing information was common.
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Author Comment

by:taz8020
ID: 40577669
No but the first record of the day is always in. Can it not have a query that numbers the logs per user and on a daily basis then odds would be in and evens would be out?
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Expert Comment

by:ScottPletcher
ID: 40577672
SELECT Name, MIN(Date) AS [In], MAX(Date) AS [Out],
    LEFT(CONVERT(varchar(10), DATEADD(MINUTE, DATEDIFF(MINUTE, MIN(DATE), MAX(Date)), 0), 8), 5) AS [Time In]
FROM (
    SELECT Name, Date,
        ROW_NUMBER() OVER(PARTITION BY Name ORDER BY Date) - 1 AS row_num
    FROM table_name
) AS derived
GROUP BY Name, row_num / 2
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Author Comment

by:taz8020
ID: 40577954
Scott that is great, is there a way to start it each day. Just the way it is, if there is a duplicate clock in one day the following day it look like they have been in since they clocked out. hope you know what I mean
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Accepted Solution

by:
ScottPletcher earned 500 total points
ID: 40578010
Yeah, assuming you don't have shifts that cross days :-) :
...
ROW_NUMBER() OVER(PARTITION BY Name, DATEADD(DAY, DATEDIFF(DAY, 0, Date), 0) ORDER BY Date) - 1 AS row_num
...
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Author Comment

by:taz8020
ID: 40579297
It now starts each day per user with a 0 but when I put it together it selects a different day for the out Max date. Is there something I am doing wrong?
SELECT Name, MIN(Date) AS [In], MAX(Date) AS [Out],
     LEFT(CONVERT(varchar(10), DATEADD(MINUTE, DATEDIFF(MINUTE, MIN(DATE), MAX(Date)), 0), 8), 5) AS [Time In]
 FROM (
     SELECT Name, Date,
         ROW_NUMBER() OVER(PARTITION BY Name, DATEADD(DAY, DATEDIFF(DAY, 0, Date), 0) ORDER BY Date) - 1 AS row_num
     FROM table_name
 ) AS derived
 GROUP BY Name, row_num / 2 

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Author Closing Comment

by:taz8020
ID: 40579299
Sorry being dull, got it thank you so much
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