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Count on group footer

Posted on 2015-01-29
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Last Modified: 2015-01-29
Hi Experts,
I'm working on a report and having problem to count on the group footer.  In the report, I have Date, TagNo, Chair (store as "C" in the table), Desk (store as "D" in the table).  My report only show Date, TagNo, Chair, Desk but group by Date.  so the Date has header and footer. here is the report look like:

1/2/15 (date)
    C0001 (TagNo)          Chair (C)
    C0002                         Desk (D)
    C0003                         Chair (C)

I want to count how many chair and how many desk on this date, so on the Date footer will show : Total of Chair : 2  Total of Desk : 1

here is the code I put in the control source of the Text box on the Date footer:
Total of Chair: =Count([Type]="C")
Total of Desk: =Count([TYPE]="D")

but both show as 2 not one is 2 and one is 1, do not know why it happens.

Thanks,
0
Comment
Question by:urjudo
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7 Comments
 
LVL 74

Expert Comment

by:Jeffrey Coachman
ID: 40577704
Try something like this in the Date footer:

=Dcount("Type","YourTable","YourDate=" & "#" & YourDate & "#" & " AND Type='C'")
=Dcount("Type","YourTable","YourDate=" & "#" & YourDate & "#" & " AND Type='D'")

JeffCoachman
0
 
LVL 57

Accepted Solution

by:
Jim Dettman (Microsoft MVP/ EE MVE) earned 400 total points
ID: 40577711
Use:

=Sum(IIF([Type]="C",1,0))

and:

=Sum(IIF([Type]="D",1,0))

Jim.
0
 
LVL 57
ID: 40577717
Count(<expression>) just tally's up the count of records where a field (or fields) is not null.

Jim.
0
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LVL 74

Expert Comment

by:Jeffrey Coachman
ID: 40577719
What *exactly* is stored in the Type field?
"C" or "Chair"
"D" or "Desk"
or even:
"Chair (C)"
and
 "Chair (D)"
My post presumes "C" or "D"
0
 
LVL 74

Assisted Solution

by:Jeffrey Coachman
Jeffrey Coachman earned 100 total points
ID: 40577727
I think Jim's Post would works better for you.
My post presumes that you have no other filters in the Report's Recordsource (and was untested)
0
 

Author Closing Comment

by:urjudo
ID: 40577757
Thank you!!!
0
 
LVL 74

Expert Comment

by:Jeffrey Coachman
ID: 40577774
If Jim's post worked for you, ...you did not have to accept my post as assisting.
Jeff
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