Simple Pivot query

Posted on 2015-01-30
Last Modified: 2015-02-11
I've never done a pivot query.  I need a simple pivot query.

I have a table that has records of "names", with a FK that column.  For example

FK      NAME
1         "Joe"
1         "Frank"
1         "Harold"
2         "Sue"
2         "Rachel"
etc, etc.

I need two (or however many) records based on FK, like

 "Joe", "Frank", "Harold"
"Sue", "Rachel"
Question by:HLRosenberger
LVL 33

Assisted Solution

ste5an earned 167 total points
ID: 40580177
It's not a pivot, its row value concatenation. Normally you use the FOR XML PATH clause. E.g.

USE master;

WITH    Data
          AS ( SELECT   QUOTENAME( AS TableName ,
                        UPPER(LEFT(, 1)) AS FirstLetter
               FROM     sys.tables T
    SELECT  O.FirstLetter ,
            STUFF(( SELECT  ', ' + I.TableName
                    FROM    Data I
                    WHERE   I.FirstLetter = O.FirstLetter
                    XML PATH('')
                  ), 1, 2, '') AS TableNames
    FROM    Data O
    GROUP BY O.FirstLetter;

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LVL 12

Assisted Solution

by:Habib Pourfard
Habib Pourfard earned 333 total points
ID: 40580390
You could write:
       STUFF((SELECT (', ' + NAME) FROM dbo.Names T2
       WHERE T1.FK = T2.FK
       FOR XML PATH ('')), 1, 2, '') [Names]
FROM dbo.Names T1

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LVL 65

Expert Comment

by:Jim Horn
ID: 40580400
Give the attached code a whirl.
For some reason my EE UI is not allowing me to post this in a code block.
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Author Comment

ID: 40580406
ok, I'm having trouble.  The data I need is in a joined table, admin_ethnicity.  Here's my query that returns all the rows based on where [FK_resource_home] = 225:  

SELECT [FK_resource_home],
  FROM .[dbo].[resource_home_ethnicity_preference]
  inner join admin_ethnicity ON admin_ethnicity.ID = [resource_home_ethnicity_preference].[FK_ethnicity]
 where [FK_resource_home] = 225

I get a result like this:
225   Caucasian
225  Hispanic or Latino

I want one row like this:

Caucasian; Hispanic or Latino;
LVL 12

Accepted Solution

Habib Pourfard earned 333 total points
ID: 40580426
WITH Names AS (
SELECT [FK_resource_home],
  FROM .[dbo].[resource_home_ethnicity_preference]
  inner join admin_ethnicity ON admin_ethnicity.ID = [resource_home_ethnicity_preference].[FK_ethnicity]
 where [FK_resource_home] = 225

 SELECT T1.[FK_resource_home],
       STUFF((SELECT (', ' + name) FROM Names T2
       WHERE T1.[FK_resource_home] = T2.[FK_resource_home]
       ORDER BY name
       FOR XML PATH ('')), 1, 2, '') [Names]
FROM Names T1
GROUP BY [FK_resource_home]

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Author Closing Comment

ID: 40604053
thanks to all.

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