Solved

Error Message On Add New Record

Posted on 2015-01-31
6
64 Views
Last Modified: 2015-01-31
I am getting this error message when I try to add a new record.
"Column count doesn't match value count at row 1"

<?php
		  include("7conn.php");
		  $mode=$_GET["mode"];
		  if($mode=="add") {
		  	$recordCust=$_POST["recordCust"];
			$recordSite=$_POST["recordSite"];
			$recordUser=$_POST["recordUser"];
			$recordPass=$_POST["recordPass"];
			$sql="insert into records(record,Cust,recordSite,recordUser, recordPass, recordDateAdded) values(" . $_SESSION['clientID'] . "'$recordSite','$recordUser','$recordPass', Now())";
			$result=mysql_query($sql,$connection) or die(mysql_error());
			header("location: clientlogin.php");
		  } elseif($mode=="update") {
		  	$recordSite=$_POST["recordSite"];
			$recordUser=$_POST["recordUser"];
			$recordPass=$_POST["recordPass"];
			$recordId = $_POST["recordId"];
			$sql="update records set recordSite='$recordSite',recordUser='$recordUser',recordPass='$recordPass'  where recordId='$recordId'";
			//echo $sql;
			$result=mysql_query($sql,$connection) or die(mysql_error());
    		header("location: clientlogin.php");
		  }
?>

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0
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Question by:DS928
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6 Comments
 
LVL 31

Expert Comment

by:Marco Gasi
ID: 40581663
You are passing 6 columns and only 5 values.
0
 
LVL 31

Expert Comment

by:Marco Gasi
ID: 40581666
record                                
Cust                                      $_SESSION['clientID']
recordSite                           $recordSite
recordUser                         $recordUser
recordPass                         $recordPass
recordDateAdded             Now()

Probably record is auto_increment, so you can just drop it from the query and this will work. Otherwise you have to provide a value for record column.
0
 
LVL 110

Expert Comment

by:Ray Paseur
ID: 40581793
This line appears to be missing a comma after the session data:

$sql="insert into records(record,Cust,recordSite,recordUser, recordPass, recordDateAdded) values(" . $_SESSION['clientID'] . "'$recordSite','$recordUser','$recordPass', Now())";

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You might also want to learn about how to escape the input data before using it in a query.  And, not a minute too soon, PHP is doing away with support for the MySQL extension, so you would want to avoid writing code that you know is obsolete.  It would be a better choice to drop MySQL and move to one of the supported extensions.
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Author Comment

by:DS928
ID: 40581870
I updated this and still getting an error message.
"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''66','66','66', Now())' at line 1"

<?php
//set_error_handler("var_dump");
		  include("7conn.php");
		  $mode=$_GET["mode"];
		  if($mode=="add") {
		  	$recordCust=$_POST["recordCust"];
			$recordSite=$_POST["recordSite"];
			$recordUser=$_POST["recordUser"];
			$recordPass=$_POST["recordPass"];
			$sql="insert into records(recordCust,recordSite,recordUser, recordPass, recordDateAdded) values(" . $_SESSION['clientID'] . ",'$recordSite','$recordUser','$recordPass', Now())";
			$result=mysql_query($sql,$connection) or die(mysql_error());
			header("location: clientlogin.php");
		  } elseif($mode=="update") {
		  	$recordSite=$_POST["recordSite"];
			$recordUser=$_POST["recordUser"];
			$recordPass=$_POST["recordPass"];
			$recordId = $_POST["recordId"];
			$sql="update records set recordSite='$recordSite',recordUser='$recordUser',recordPass='$recordPass'  where recordId='$recordId'";
			//echo $sql;
			$result=mysql_query($sql,$connection) or die(mysql_error());
    		header("location: clientlogin.php");
		  }
?>

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0
 
LVL 31

Accepted Solution

by:
Marco Gasi earned 500 total points
ID: 40581920
Try adding quotes to $_SESSION['clientID']

$sql="insert into records(recordCust,recordSite,recordUser, recordPass, recordDateAdded) values('" . $_SESSION['clientID'] . "','$recordSite','$recordUser','$recordPass', Now())";

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0
 

Author Closing Comment

by:DS928
ID: 40581935
Thank you that worked!
0

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