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mysql php

Posted on 2015-02-01
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Last Modified: 2016-06-18
Hello I have a problem with mysql.

I want us values from a another table.

This is what I got:

      $q = "SELECT voorbeeld_id, voorbeelden1, voorbeelden2, voorbeelden3, voorbeelden4, voorbeelden5, voorbeeldenfile," .
                                     "             datediff(voorbeelden3, CURDATE()) AS voorbeelden4" .
                                     "  FROM voorbeelden WHERE klant_id = :klant_id" .
                                     "  ORDER BY voorbeeld_id ASC";
                              $sth = $db->prepare($q);
                              $sth->execute(array("klant_id" => $klant_id));


Now I want also from the table "klanten"  the values of "leverancier". I hope someone can help me.
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Question by:Ron Baas
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3 Comments
 
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Accepted Solution

by:
Daniel Wilson earned 500 total points
ID: 40583132
Do you want both the value from voorbeelden and from klanten in the same query?  How are the tables voorbelden and klanten related?  Do they share a field?  Perhaps klant_id?

If so ... this query should work.  Or be close enough that you can adjust it.
      $q = "SELECT voorbeeld_id, voorbeelden1, voorbeelden2, voorbeelden3, voorbeelden4, voorbeelden5, voorbeeldenfile," .
                                     "             datediff(voorbeelden3, CURDATE()) AS voorbeelden4, leverancier" .
                                     "  FROM voorbeelden inner join klanten on voorbeelden.klant_id = klanten.klant_id
                                        WHERE voorbeelden.klant_id = :klant_id" .
                                     "  ORDER BY voorbeeld_id ASC";
                              $sth = $db->prepare($q);
                              $sth->execute(array("klant_id" => $klant_id));

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Author Comment

by:Ron Baas
ID: 40612837
thanks Daniel its working now with this code:

      $q = "SELECT voorbeeld_id, voorbeelden1, voorbeelden2, voorbeelden3, voorbeelden4, voorbeelden5, voorbeeldenfile,  leverancier," .
                                     "             datediff(voorbeelden3, CURDATE()) AS voorbeelden4" .
                                     "  FROM voorbeelden inner join klanten on voorbeelden.klant_id = klanten.klant_id
                                        WHERE voorbeelden.klant_id = :klant_id" .
                                     "  ORDER BY voorbeeld_id ASC";
                              $sth = $db->prepare($q);
                              $sth->execute(array("klant_id" => $klant_id));
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