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sql query for weeks

I need to create a query which will return dates from the 45 to 90 days from now. The number of session per week should 9 or more and number of sessions per week is only calculated per working days (Satarday / sundays excluded).

I start doing the query but seems to be stock in here ...

SELECT DATEADD(day, DATEDIFF(day, 0, SU.sessionStart), 0) AS reservedOn,
 COUNT(SU.sessionKey) AS Count,
 DATEDIFF(day,getDAte(),SU.sessionStart),l2.locationKey 
 
 FROM SessionUnit SU 
 Inner join Session S on S.sessionKey = SU.sessionkey 
 inner join product P on p.productKey = S.productKey 
 CROSS APPLY ( SELECT item AS SPLITLOCATIONKEY from DelimitedSplit8K(S.locationKeyList, ',') )as ca 
 INNER JOIN location AS L2 ON CA.SplitLocationKey = L2.LocationKey AND (L2.locationKey in (225,228,260) OR S.locationKey in (225,228,260)) 
 WHERE convert(DATE,su.sessionStart) >= DateAdd("d",45,getDate()) 
 AND convert(DATE,su.sessionStart) <= DateAdd("d",90,getDate()) 
and ((DATEPART(dw, su.sessionStart) + @@DATEFIRST) % 7) NOT IN (0, 1)
 AND p.productKey = 2 
 GROUP BY DATEADD(day, DATEDIFF(day, 0, sessionStart), 0),DATEDIFF(day,getDAte(),SU.sessionStart),l2.locationKey 

 ORDER BY reservedOn 

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erikTsomik
Asked:
erikTsomik
  • 4
1 Solution
 
erikTsomikSystem Architect, CF programmer Author Commented:
Any suggestions
0
 
Scott PletcherSenior DBACommented:
What is the specific issue you're having?

Some minor tweaks would help the SQL perform, but other than that, what about it is not working?


SELECT
    DATEADD(day, DATEDIFF(day, 0, SU.sessionStart), 0) AS reservedOn,
    COUNT(SU.sessionKey) AS Count,
    DATEDIFF(day,getDAte(),SU.sessionStart),l2.locationKey
FROM SessionUnit SU
Inner join Session S on S.sessionKey = SU.sessionkey
inner join product P on p.productKey = S.productKey
CROSS APPLY (
    SELECT item AS SPLITLOCATIONKEY
    from DelimitedSplit8K(S.locationKeyList, ',')
)as ca
INNER JOIN location AS L2 ON CA.SplitLocationKey = L2.LocationKey AND (L2.locationKey in (225,228,260) OR S.locationKey in (225,228,260))
WHERE
    su.sessionStart >= DateAdd(day,45,dateadd(day, datediff(day, 0, getdate()), 0))
AND su.sessionStart <  DateAdd(day,91,dateadd(day, datediff(day, 0, getdate()), 0))
AND datediff(day, 0, su.sessionStart) % 7 not in (5, 6) --always works regardless of date settings
AND p.productKey = 2
GROUP BY DATEADD(day, DATEDIFF(day, 0, sessionStart), 0),DATEDIFF(day,getDAte(),SU.sessionStart),l2.locationKey

ORDER BY reservedOn
0
 
erikTsomikSystem Architect, CF programmer Author Commented:
The question is I need the number of session for the week to be >=9. What I am trying to is to say it was done 3 sessions on 4/20,3 sessions on 4/21, 3 sessions 4/22 I want to grayed out the whole week on jquery ui datepicker. SO I need to know every single day but the count for the week must be 9 or more.
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erikTsomikSystem Architect, CF programmer Author Commented:
O r event better example the client did 9 sessions on 4/15 I want to great out the whole week from 4/13 to 4/17 because he max out number 9 sessions per week
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erikTsomikSystem Architect, CF programmer Author Commented:
I came up with query But now how would I get the end date .If I get an end date than I can do the range

Select WeekStart =
  dateadd(week, datediff(week, 0, SU.sessionStart), 0)
  ,CountID = Count(S.sessionKey)
 
FROM SessionUnit SU
Inner join Session S on S.sessionKey = SU.sessionkey
inner join product P on p.productKey = S.productKey
CROSS APPLY (
    SELECT item AS SPLITLOCATIONKEY
    from DelimitedSplit8K(S.locationKeyList, ',')
)as ca
INNER JOIN location AS L2 ON CA.SplitLocationKey = L2.LocationKey AND (L2.locationKey in (225,228,260) OR S.locationKey in (225,228,260))
WHERE  su.sessionStart >= DateAdd(day,45,dateadd(day, datediff(day, 0, getdate()), 0))
AND su.sessionStart <  DateAdd(day,91,dateadd(day, datediff(day, 0, getdate()), 0))
AND datediff(day, 0, su.sessionStart) % 7 not in (5, 6) --always works regardless of date settings
AND p.productKey = 2  and SU.instructorKey = 42
GROUP BY
 dateadd(week, datediff(week, 0, SU.sessionStart), 0)
0

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