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jquery/ajax to code behind

Posted on 2015-02-06
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162 Views
Last Modified: 2015-03-12
I have below object called resultObj  from jquery,
how can I pass to code behind c#?

  $.ajax({
                cache: false,
                type: "GET",
                async: false,
                dataType: "json",
                contentType: 'text/plain',
                url: GetDealerList + encodeURIComponent("(06234,'1111,asdfasdfasd,asdfasfasdf')"),
                success: function (data) {
                    $('#data').html(data);
                    alert(data);
                    if (data == null)
                        return;
                    resultObj = jQuery.parseJSON(data);
                    if (resultObj.Status != 'Failed') {
                        $('#json').html(createDealer(resultObj.Data));
                    }
                },
                error: function (xhr) {
                    $('#data').html(xhr.responseText);
                    //alert(xhr.responseText);

                }
            });
0
Comment
Question by:ITsolutionWizard
  • 4
  • 3
7 Comments
 
LVL 42

Expert Comment

by:Rob Jurd, EE MVE
ID: 40595101
As described here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify use JSON.stringify to covert the js object to JSON format.  Then include that in your ajax request.
0
 

Author Comment

by:ITsolutionWizard
ID: 40595174
I need some sample codes to support what you mentioned....Thanks
0
 
LVL 42

Expert Comment

by:Rob Jurd, EE MVE
ID: 40595180
url: GetDealerList + encodeURIComponent(JSON.stringify(resultObj)),
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Author Comment

by:ITsolutionWizard
ID: 40600044
inside of code behind. how can i capture it?
0
 
LVL 42

Expert Comment

by:Rob Jurd, EE MVE
ID: 40600437
The querystring will be sent and made available to your webmethod. I'm not familiar with .net but usually done with the Request class
0
 

Author Comment

by:ITsolutionWizard
ID: 40600807
Not sure which property should be used from request.
0
 
LVL 42

Accepted Solution

by:
Rob Jurd, EE MVE earned 500 total points
ID: 40602224
like this, you need to add the data attribute to your ajax call.  Then the variable "result" will be available via the Request['result']

 $.ajax({
                cache: false,
                type: "GET",
                async: false,
                dataType: "json",
                contentType: 'text/plain',
               data: {
                       "result": encodeURIComponent(JSON.stringify(resultObj))
                },
               url: GetDealerList,
                success: function (data) {
                    $('#data').html(data);
                    alert(data);
                    if (data == null)
                        return;
                    resultObj = jQuery.parseJSON(data);
                    if (resultObj.Status != 'Failed') {
                        $('#json').html(createDealer(resultObj.Data));
                    }
                },
                error: function (xhr) {
                    $('#data').html(xhr.responseText);
                    //alert(xhr.responseText);

                }
            });
0

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