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Remote Desktop 2012 R2 (Citrix) need to run Access 2010 and Access 2013 together

Posted on 2015-02-09
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Last Modified: 2016-05-31
I need to run Access 2010 and Access 2013 together in a Windows 2012 R2 Remote Desktop setup to support Citrix XenApp 7.6.  I installed Access 2010 (only), then installed the full Office 2013 suite.  Now when I try to open Access 2010 it does a reinstall.  If I then open Access 2013 it will do a reinstall.  How can I prevent the reinstall from running?

Ken ...
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Question by:SpokaneISD
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12 Comments
 
LVL 57
ID: 40600642
Ken,

 With the Microsoft installs you cannot.  Only Sagekey has licked that particular problem:

http://www.sagekey.com/installation_access.aspx

Jim.
0
 
LVL 57
ID: 40600646
Note there is a free 14 day demo there you can try out.

Also, this is for installing the runtime, not the full version.  You'd have to give them a call and see if it's possible to do an isolated install on the full version.

 I would think so because the runtime is nothing more than the full version with design features disabled, but I don't know that for sure, so ask if you need that.

Jim.
0
 

Author Comment

by:SpokaneISD
ID: 40600991
Jim,
Thanks for the reply.  I did find KB2784668, but I was hoping someone had found a way around this.  Looks like I have to come up with something else.

Ken ...
0
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LVL 57
ID: 40601014
Ken,

  Yes, what the MSKB article states correct and has always been true (oldest to newest and in separate directories).  Right now I have one machine with A97, A2000, A2003, A2007, A2010 all installed.

 However in regards to your question specifically, there's no way around the re-register/repair process that occurs with 2002 and up, at least not with the way Microsoft installs.

Jim.
0
 

Author Comment

by:SpokaneISD
ID: 40601182
I'm open to any creative way to get this to work.  A third-party option that we have to pay a fee for isn't going to fly.  I just need to have Access 2010 (as the only Office 2010 suite member) installed on the same Citrix server as the full Office 2013 suite.  My hope was that Office 2013 could be set up as the default Office applications with the Access 2010 being executed via the full path.  

I have Access 2010 installed to the Office\14 folder and Office 2013 installed to the Office\15 folder so they have different paths.

Ken ...
0
 
LVL 57

Accepted Solution

by:
Jim Dettman (Microsoft MVP/ EE MVE) earned 500 total points
ID: 40601252
Ken,

<<I'm open to any creative way to get this to work.  A third-party option that we have to pay a fee for isn't going to fly.>>

 Sorry, but as long as more than one version runs within the same OS, each will re-register every time they start.

 This is a long standing problem with Access and SageKey is the only one I know that has figured out how to deal with it.

 There is also Inno setup, but I believe using it ends up with the same problem.

 Your only other option is a second TS Server.

Jim.
0
 
LVL 84
ID: 40605536
There is also Inno setup, but I believe using it ends up with the same problem.
Inno is just a Windows Installer tool, and would not be the same as SageKey. I believe Sagekey writes specific registry keys when the application starts, and then rewrites them when the application is finished.

Also - for the most part, 2013 can run anything that 2010 can run, so you might investigate installing ONLY 2013. This might involve upgrading any 2010 apps to 2013, but that's a quick and simple process.
0
 

Author Comment

by:SpokaneISD
ID: 40605850
Scott,
Thanks for the reply.  The problem is that we have some in-house written Access applications that have some custom controls that don't work in Access 2013.  I'm trying to get them to rewrite the app, but the development staff tell me they don't have the time for that.

Ken ...
0
 
LVL 84
ID: 40605859
Then, as Jim said, you're stuck with either (a) putting up with the reinstall mess or (b) running two separate RDS setups.
0
 

Author Comment

by:SpokaneISD
ID: 40605933
I might also look at App-V.  I have no experience with App-V, but it might be the best solution in this case.

Ken ...
0

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