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firstLast6

Hi,
I was working on below challenge to find 6 at first and last position of array.

http://codingbat.com/prob/p185685

public boolean firstLast6(int[] nums) {



if(nums.contains(6))
{
return true;
}

else
{
return false;
}
  
}

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i put some  code. Not exactly sure how to go about it. please advise
0
gudii9
Asked:
gudii9
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2 Solutions
 
gudii9Author Commented:
public boolean firstLast6(int[] nums) {

int firstInt=nums[0];
int numsLength=nums.length;
int lastInt=nums[numsLength-1];

if(firstInt==6)
{
return true;
}

if(lastInt==6)
{
return true;
}

else
{
return false;
}
  
}

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i made changes and passed the tests. i wonder how i can improve my code. Please advise
0
 
ozoCommented:
I don't see anything wrong with your code.
You can also do it without the temporary variables:
  return nums[0]==6 || nums[nums.length-1]==6;
0
 
gudii9Author Commented:
public boolean firstLast6(int[] nums) {
  return nums[0]==6 || nums[nums.length-1]==6;
}

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above passed all tests too in just one single simple line. couple  of questions here
1. What are temporary variables are there any permenant variables too if yes which to use when
2. How the false scenario taken care automatically how it passed all the tests( returning true is somewhat fine but returning false scenario not clear)

please advise
0
 
ozoCommented:
there aren't really permanent variables, but some variables can be more temporary than others
http://docs.oracle.com/javase/tutorial/java/javaOO/variables.html

nums[0]==6 and nums[nums.length-1]==6 are either true or false.
0
 
Nadia SobnomCommented:
public boolean firstLast6(int[] nums) {
  return nums[0] == 6 || nums[nums.length - 1] == 6;
}

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0

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