sameFirstLast
hi,
I am trying below challenge
http://codingbat.com/prob/p118976
i am failing in one test case
please advise
I am trying below challenge
http://codingbat.com/prob/p118976
i am failing in one test case
public boolean sameFirstLast(int[] nums) {
int numsLen=nums.length;
int first=nums[0];
int last=nums[numsLen-1];
if(numsLen>=1&&first==last)
return true;
return false;
}Expected Run
sameFirstLast({1, 2, 3}) → false false OK
sameFirstLast({1, 2, 3, 1}) → true true OK
sameFirstLast({1, 2, 1}) → true true OK
sameFirstLast({7}) → true true OK
sameFirstLast({}) → false Exception:java.lang.ArrayIndexOutOfBoundsException: 0 (line number:3) X
sameFirstLast({1, 2, 3, 4, 5, 1}) → true true OK
sameFirstLast({1, 2, 3, 4, 5, 13}) → false false OK
sameFirstLast({13, 2, 3, 4, 5, 13}) → true true OK
sameFirstLast({7, 7}) → true true OK
other testsplease advise
SOLUTION
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numsLen>=1&& is unneccessary
and at that point, you can just
return first==last;
or, using numsLen>=1&& you can make the if(numsLen==0){ unnecessary
and at that point, you can just
return first==last;
or, using numsLen>=1&& you can make the if(numsLen==0){ unnecessary
ASKER
And rather than:
if (first == last)
return true ;
return false ;
you can just return whether "first == last"
return (first == last) ;instead of doing in 2 steps like checking and then returning we are doing in one step in return itself comparing so that i will automatically give true false in return statement right?
please advise
SOLUTION
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instead of doing in 2 steps like checking and then returning we are doing in one step in return itself comparing so that i will automatically give true false in return statement right?
Yes that's right. We're replacing 3 lines of code with 1 - which is good because it's simpler. And we're also removing a conditional (the "if" test) so the code always executes the same lines of code - which is also good.
Rather than:
if (first == last) {
// Sometimes we run code in here
return true ;
}
// Sometimes we run code here
return false ;
We have now:
// Always run this code
return (first == last) ;
It's best to avoid branches and conditional statements in your code where possible. It makes bugs less likely.
Doug
ASKER CERTIFIED SOLUTION
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Thanx 4 axxepting
ASKER
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i think i oredere edge case and passed all tests. I wonder how to improve my code. please advise