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Java file path help

Posted on 2015-02-16
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Last Modified: 2015-02-17
Hello there,

I have this code like this

storeHelper.process(new File("."), false);

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and below is the description of that method.

public void process(File dropDirectory,
                    boolean isRecursive)
             throws TemplateStoreException,
                    IOException,
                    NoConvertersRunningException
Drop a whole directory of templates into the store optionally processing sub-directories.
Parameters:
dropDirectory - the directory to pick up documents from.
isRecursive - true to recursively drop sub-directories; false to only process the given directory.
Throws:
TemplateStoreException - if the underlying template store has an error
IOException - if an IO error occurs
NoConvertersRunningException - if there are no converters running

i want to know what does this File(".") do. i dont seem to get this.

cheers
zolf
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Question by:zolf
2 Comments
 
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dpearson earned 500 total points
ID: 40613680
In Linux "." is the current working directory - so File(".") is attempting to establish the path to the current directory.

E.g. If your current working directory is /usr/myfolder
then "." is "/usr/myfolder"
and ".." is the parent - or "/usr"

Does that make sense?

Doug
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Author Closing Comment

by:zolf
ID: 40613840
thanks
0

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