asked on

mysql left join

Not sure why I am getting this error. I have done plenty of left joins before. Maybe I need a fresh set of eyes.

SELECT
	`orders`.`itemOptions`,
	`products`.`product_id`,
	`products`.`product_number`,
	`products`.`title`,
	`products`.`price`
		
FROM
	`orders`,`products`

LEFT JOIN `options` on `orders`.`itemOptions` = `options`.`optionID`

WHERE
	`orders`.`orderID` = '113'
	AND `orders`.`itemsOrdered` = `products`.`product_id`

Open in new window

Error: #1054 - Unknown column 'orders.itemOptions' in 'on clause'

Schema:

CREATE TABLE IF NOT EXISTS `options` (
`optionID` int(11) NOT NULL AUTO_INCREMENT,
`name` text NOT NULL,
PRIMARY KEY (`optionID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=9 ;

CREATE TABLE IF NOT EXISTS `products` (
`product_id` int(250) NOT NULL AUTO_INCREMENT,
`cat_id` varchar(250) NOT NULL,
`product_number` varchar(50) DEFAULT NULL,
`title` varchar(250) NOT NULL,
`text` text,
`photo` varchar(250) DEFAULT NULL,
`price` decimal(5,2) DEFAULT NULL,
`options` text,
`online` int(11) DEFAULT '0',
`order` int(11) DEFAULT '0',
`noShipping` int(11) DEFAULT '0',
`noTax` int(11) DEFAULT '0',
PRIMARY KEY (`product_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=101 ;

CREATE TABLE IF NOT EXISTS `orders` (
`orderID` int(11) NOT NULL AUTO_INCREMENT,
`f_name` varchar(30) DEFAULT '',
`l_name` varchar(30) DEFAULT '',
`email` text,
`phone` varchar(20) DEFAULT '',
`address` text,
`address2` text,
`city` varchar(30) DEFAULT '',
`state` varchar(30) DEFAULT '',
`zip` varchar(20) DEFAULT '',
`s_address` text,
`s_address2` text,
`s_city` varchar(30) DEFAULT '',
`s_state` varchar(30) DEFAULT '',
`s_zip` varchar(20) DEFAULT '',
`comments` text,
`ship_comments` text,
`cardName` text,
`cardType` varchar(20) DEFAULT '',
`cardNumber` varchar(30) DEFAULT '',
`exp` varchar(20) DEFAULT '',
`cvv` varchar(10) DEFAULT '',
`costShipping` double DEFAULT NULL,
`costTax` double DEFAULT NULL,
`costDiscount` double DEFAULT NULL,
`costTotal` double DEFAULT NULL,
`itemsOrdered` text,
`itemOptions` varchar(200) DEFAULT NULL,
`itemsQuantity` text,
`dateAdded` timestamp NULL DEFAULT NULL,
PRIMARY KEY (`orderID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=122 ;

ASKER CERTIFIED SOLUTION

Dave Baldwin

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gr8gonzo

Seems like maybe there's a typo in there somewhere. Simplify it down to using table aliases and lose the backticks:

SELECT
      o.itemOptions,
      p.product_id,
      p.product_number,
      p.title,
      p.price
FROM
      orders o,
      products p
LEFT JOIN options op ON o.itemOptions = op.optionID
WHERE
      o.orderID = 113
      AND o.itemsOrdered = p.product_id

I say this because you are already selecting orders.itemOptions in your SELECT statement, so if the error says the column doesn't exist, then it would have thrown the error on the SELECT portion first. So it sounds like there's some bad whitespace or something in there somewhere.

Dave Baldwin

o.itemOptions = op.optionID will never match because they are different 'types'.

Guy Hengel [angelIII / a3]

please do not match JOIN with "non-join" syntax
also, please start to use aliases in your queries (as shown by the above comments)
https://www.experts-exchange.com/Database/Miscellaneous/A_11135-Why-should-I-use-aliases-in-my-queries.html

SELECT
	o.`itemOptions`,
	p.`product_id`,
	p.`product_number`,
	p.`title`,
	p.`price`
FROM 	`orders` o
JOIN `products` p
   ON  o.`itemsOrdered` =  p.`product_id`
LEFT JOIN `options` op on  o.`itemOptions` =  op.`optionID`
WHERE 	o.`orderID` = '113'

Open in new window

Robert Saylor

ASKER

Thanks, I understand the issue now with the data type. I will most likely have to write it as a nested query now but that is life.

Guy Hengel [angelIII / a3]

I agree that this may be some issue, but not the explanation to the error provided:

Error: #1054 - Unknown column 'orders.itemOptions' in 'on clause'

Robert Saylor

ASKER

This should be closed or deleted. I did not get a solid answer to my question.

Guy Hengel [angelIII / a3]

how did you solve your issue, then?

Robert Saylor

ASKER

Guy I did not solve it. I wish my question to be removed.

Robert Saylor

ASKER

I've requested that this question be deleted for the following reason:

I did not get the answer I need and I will have to re-write this query.

gr8gonzo

Please do not close the question with a simple "re-write" self solution. Part of this whole process is that someone else will come along with the same question and if they find your question and answer, it will help them out. If you delete it, that help goes away with all of the above effort.

Dave's original answer #40620412 is 100% correct. I tried it out on a local test database and that is indeed the resulting error message (a bizarre error message for that problem, but it's true). So please accept his answer as the solution and then you can re-write the query.

gr8gonzo

Sorry, that should have been an objection.

Robert Saylor

ASKER

Please let this close GUY ok. Like I said the first time I accept this as the issue.