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Find Monday in iso_week 1

Posted on 2015-02-20
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Last Modified: 2015-02-20
Hi!

I need a sql query to provide me the Monday in iso_week 1 for any given year.

in 2015 it should return '2014-12-29'
in 2016 it should return '2016-01-04'
in 2017 it should return '2017-01-02'

Thanks,
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Question by:intimenordic
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2 Comments
 
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Accepted Solution

by:
Phillip Burton earned 2000 total points
ID: 40620857
Either:

select dateadd(day,2-datepart(dw,'20130101')+iif(datepart(dw,'20130101')>5,7,0),'20130101') as ISOWeek1

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or, if you want to define it once:

declare @year as char(4)
set @year = '2027'

select dateadd(day,2-datepart(dw,@year + '0101')+iif(datepart(dw,@year + '0101')>5,7,0),@year + '0101') as ISOWeek1

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Author Closing Comment

by:intimenordic
ID: 40620863
Perfect! Just used getdate for declaring, since this is a runtime thing.

declare @year as char(4)
set @year = year(getdate())
select dateadd(day,2-datepart(dw,@year + '0101')+iif(datepart(dw,@year + '0101')>5,7,0),@year + '0101') as ISOWeek1

Thanks, and have a great weekend!
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