I need help with a query, probably involving the MIN function

I need help figuring out a sql query. I have tried using the MIN statement to get what I need, but still can't figure this out.

Suppose I have many clients with the same First,  and Last Name,
and possibly the same middle initial. The only thing really distinguishing
these records, is that each Code value is different for each record.

So how would I return only one record for people with similar first, middle and last names?
Plus I want the record which has the shortest length Code within a group of similar sounding names.
So notice that one of the duplicate named people will have a code which is the shortest in length. That is
the one I want. (Also, I want the resulting query to return the resulting query data into a temp table)

So for example for this table data :

First       MI Last    Code
Drake    B  Hansen   12345
Drake         Hansen   12345A
Drake    T   Hansen   12345B
Berry     K   Mojo        98988
Mary     B   Jones        55687
Mary           Jones        55687A
Mary      H  Jones        55687B

I want my query to return the following  :

Drake  B Hansen   12345
Berry  K Mojo        98988
Mary   B   Jones     55687

Attached is a scripted table with data, if that helps
SampleTable.txt
LVL 2
brgdotnetcontractorAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

BullfrogSoftwareCommented:
Is the 'Code' always going to be a numeric, then the same numeric with alphabetic characters at the end?  If so, you could just check that the code 'IsNumeric' and return all of the rows that are.
0
arnoldCommented:
Select first,mi,last,min(code) from tablename group by (first + last) [,code], MIA

The [] optional if without it you get an error.
0
brgdotnetcontractorAuthor Commented:
Arnold, I can't get that to work :

Msg 102, Level 15, State 1, Line 29
Incorrect syntax near ',Code'.

Select FirstName,MI,LastName,min(CODE) from Clients group by (FirstName + LastName) [,Code]
0
Ultimate Tool Kit for Technology Solution Provider

Broken down into practical pointers and step-by-step instructions, the IT Service Excellence Tool Kit delivers expert advice for technology solution providers. Get your free copy now.

arnoldCommented:
You need to remove the [] surrounding the code
And will likely need to add MI at the end

Select first,mi,last,min(code) from tablename group by (first + last)[,code, MIA

The [] optional if without it you get an error.
0
Dale FyeCommented:
SELECT T1.First, T1.MI, T1.LAST, T1.Code
FROM yourTable T1
INNER JOIN
(
SELECT First, LAST, Min(LEN(Code)) as MinLen
FROM yourTable
GROUP BY First, Last
) as T2
ON T1.First = T2.First AND T1.Last = T2.Last AND Len(T1.Code) = T2.MinLen

The subquery identifies the combinations of First, and Last, and determines the shortest length of the Code field for that combination.  You then join that subquery to your table and join on the First, Last, and Len(Code) values to identify the particular row.
0
PortletPaulfreelancerCommented:
Using ROW_NUMBER() is efficient and convenient for this style of need.

| FIRSTNAME | MI | LASTNAME |       CODE |
|-----------|----|----------|------------|
|      Brad |  T |   Grassy | 45455      |
|     Drake |  B |   Hansen | 12345      |
|      Mary |  B |    Jones | 45455      |
|     Sarah |  P |   Gisley | 8889       |

Open in new window


produced by:
select
      [FirstName], [MI], [LastName], [Code]
      from (
        select *
        , row_number() over(partition by [FirstName], [LastName]
                            order by code ASC) as rn
        from [dbo].[Clients]
     ) c
where c.rn = 1
;

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft SQL Server

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.