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ClassCastException while trying to create HttpsURLConnection

Hi,
when I am trying to create httpsURLConnection like this:
HttpsURLConnection con = (HttpsURLConnection) url.openConnection();

I am getting ClassCastException but its working fine in standalone application

JDK:1.4
Weblogic: 8

CODE SAMPLE:
import java.net.URL;
import javax.net.ssl.HttpsURLConnection;
-----
----

            URL url;
            try {

                  SSLContext ssl_ctx = SSLContext.getInstance("TLS");
                  TrustManager[] trust_mgr = get_trust_mgr();
                  ssl_ctx.init(null, trust_mgr,new SecureRandom()); // random number generator
                  HttpsURLConnection.setDefaultSSLSocketFactory(ssl_ctx
                              .getSocketFactory());

                  url = new URL("https://.......");

                  HttpsURLConnection con = (HttpsURLConnection) url.openConnection();

}catch(.....){
----
}

Please Help me to resolve this problem
Thanks you

SOLUTION

CEHJ

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SOLUTION

Jeffrey Dake

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SANJAY HALDAR

ASKER

Thanks for your responses.

I am able to resolve this. Please find updated code:

import java.net.URL;
import javax.net.ssl.HttpsURLConnection;
-----
----

URL url;
try {

SSLContext ssl_ctx = SSLContext.getInstance("TLS");
TrustManager[] trust_mgr = get_trust_mgr();
ssl_ctx.init(null, trust_mgr,new SecureRandom()); // random number generator
HttpsURLConnection.setDefaultSSLSocketFactory(ssl_ctx
.getSocketFactory());

           .getSocketFactory());

                  //url = new java.net.URL("https://......");
                  url = new URL(null,"https://....",new sun.net.www.protocol.https.Handler());

                   URI uri=null;
                  try {
                        uri = new URI(url.getProtocol(),url.getAuthority(), url.getPath(), url.getQuery(), null);
                  } catch (URISyntaxException e) {
                        e.printStackTrace();
                  }

                   url = uri.toURL();

HttpsURLConnection con = (HttpsURLConnection) url.openConnection();

}catch(.....){
----
}

Regards,
Ajaya Samanta

CEHJ

What are you doing with 'con' such that you need to know its type?

ASKER CERTIFIED SOLUTION

SANJAY HALDAR

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CEHJ

Two people showed you the reason for the problem and yet you couldn't even be bothered to respond ...

SANJAY HALDAR

ASKER

I've requested that this question be closed as follows:

Accepted answer: 0 points for SANJAY HALDAR's comment #a40646513

for the following reason:

Provided solution worked out and solved the issue.

Thanks.

CEHJ

Two people showed you the reason for the problem and yet you couldn't even be bothered to respond ...

SANJAY HALDAR

ASKER

The question was well responded that we got the solution our self, what does the last comment of CEHJ means?

SANJAY HALDAR

ASKER