Formula to extract numbers from text

I have text strings in the form

0' - Start of straight line, Road R-6 RD 0'
397' - Road R-5 RD 0', Start of straight line
9234' - Road R-29 RD 6247', End of road
6141' - Road R-1 RD 9233', Road R-29 RD 6239', End of road
739' - Road R-149 RD 0'
2534' - End of road, Road R-40 RD 2267'
0' - Start of straight line, Road R-1 RD 0', Road R-20 RD 0'

I need to extract the R- numbers and the RD values as shown in the attached file. Excel formula preferred but VBA is also acceptable.
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Saqib Husain, SyedEngineerAsked:
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As a start you can put the following in B2 of your example and copy down:
=MID(A2,FIND("R-",A2)+2,FIND(" ",A2,FIND("R-",A2))-FIND("R-",A2)-2)

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and the following into C2 of your example and copy down
=MID(A2,FIND("RD ",A2)+3,FIND("'",A2,FIND("RD ",A2))-FIND("RD ",A2)-3)

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Columns D and E represent a second pair of R- and RD in the same data. Will they always occur in pairs? Is there a limit to the number of pairs per cell in column A?
Saqib Husain, SyedEngineerAuthor Commented:
Thanks for the formulas. Yes they will always be in pairs. I have two at the moment and I think that the maximum could be 4.
ProfessorJimJamMicrosoft Excel ExpertCommented:
Hi Saqib,

please find attached solution with UDF regular expression.
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I am just curious how this can be done using formula instead of UDF
ProfessorJimJamMicrosoft Excel ExpertCommented:

It is possible with formula, but the formula would be too lengthy, so if UDF does the job, why waste time with formula?

if you want this by formula, i suggest you open a new question.
ProfJimJam is correct in that trying to do this in one long formula for the fourth instance (for example) would be too lengthy.
If you're happy to put up with some additional columns then this can be simplified somewhat as seen in the attached.

Hope that helps.
Saqib Husain, SyedEngineerAuthor Commented:
I did it myself at home and came up with this formula to be entered in b2 and copied down and across.

=IFERROR(REPLACE(REPLACE($A10,FIND(IF(MOD(COLUMN(),2),"'"," "),$A10,FIND("##",SUBSTITUTE($A10,IF(MOD(COLUMN(),2),"RD ","R-"),"##",(COLUMN()-COLUMN($B10)+2)/2))),9999,""),1,FIND("##",SUBSTITUTE($A10,IF(MOD(COLUMN(),2),"RD ","R-"),"##",(COLUMN()-COLUMN($B10)+2)/2))+1,""),"")

It is big but not huge.
The regex needs a library to be loaded.

I shall keep this open a bit for someone to improve on this formula (Barry????). If not then then ProfessorJimJam's solution shall be an assist.

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That's a pretty nifty solution. Nothing to add :-)
Saqib Husain, SyedEngineerAuthor Commented:
Found a preferred solution.
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