looking for itox() function, conversion of integer to hex string (no printf or stdio.h).

There is itoa() function from standard library that do this.

I'm using C28x device in embedded c (using code composer).

I'm looking for integer to hex string conversion

Can you suggest?


UINT16 i;
INT32 RXdataRAW[10];    // contain INT32 data from ADC device
char UART_ASCII[12];       // for string formating.
for (i=0; i<10; i++)
UARTB_String("CH1 0x");
ltoa(RXdataRAW(i), UART_ASCII);
Richard PayneChief Technology EngineerAsked:
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How are UARTB_String,  UARTB_Msg_LFCR, and ltoa defined?
Richard PayneChief Technology EngineerAuthor Commented:
itoa() come from standard library (stdlib.h), ie
int       ltoa(long val, char *buffer);

UARTB function is related to UARTB port of C28x based device. It take string in char array to UARTB port. That all you need to know....
itoa is not standard.
There is a non-standard
char *  itoa ( int value, char * str, int base );
that is supported by some compilers,
but your example used ltoa
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Richard PayneChief Technology EngineerAuthor Commented:
Hmm interesting

The data being used is 32 bit, the C28x device is 16 bit in memory but 32 bit core.

Thus the reason for ltoa() which is used for decimal ASCII, I need hex ASCII, they do not have base in ltoa()
static char d[]="0123456789abcdef";
void ltoa(unsigned long l,char a[9]){
  for(int i=8;i>0;){
int main(){
  char a[9];

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char * intToHex(unsigned int x, char buf[], int sizbuf)
    buf[--sizbuf] = '\0';
    while (sizbuf > 0 && x != 0)
        unsigned char hexdig = (unsigned char)(x%16);
        buf[--sizbuf] =  (hexdig < 10)? ('0'+hexdig) : ('a' + hexdig-10);
        x /= 16;
    return &buf[sizbuf];

int main()
    char buf[32] = { 0 };
    char * p = intToHex(0x1357ACEF, buf, 32);
    std::cout << p << std::endl;
    return 0;

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Richard PayneChief Technology EngineerAuthor Commented:
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