Access query

I have a table which contains the following fields: Day, Code and hours.
I need a query which will return all records where day and code are equal, but hours is different.
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leecettAsked:
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Saurabh Singh TeotiaCommented:
You can do something like this to do what you are looking for..

select tb1.* from 
table1 tb1
where tb1.day=tb1.code and tb1.day<>tb1.hours;

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Saurabh...
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leecettAuthor Commented:
Thanks for the prompt response, I need to clarify my question with an example:
Day,Code,Hours
1,5,8
1,4,6
1,5,7
1,4,6

Query returns these records:
1,5,8
1,5,7

As these two records have identical values for both Day and Code, but different value for hours.
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Rey Obrero (Capricorn1)Commented:
try

SELECT tblx.Day, tblx.Code, tblx.Hours
FROM tblx INNER JOIN tblx AS tblx_1 ON (tblx.Code = tblx_1.Code) AND (tblx.Day = tblx_1.Day)
WHERE (((tblx.Hours)<>[tblx_1].[hours]));
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leecettAuthor Commented:
Thanks Rey
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