<div>
I add 20kg mass which is 20000cm^3 and converted to m^3 and the addition mass is correct
</div>


I add 20kg mass which is 20000cm^3 and converted to m^3 and the addition mass is correct

<div>
&gt;&gt;<i>I add 20kg mass which is 20000cm^3 and converted to m^3 and the addition mass is correct</i><br />
<br />

<div class="indent">
this calculatuon &nbsp;gives a density equal to that of water.<br />
<br />
you have to decrease the volume of this mass in order to to increase the density!
</div>
</div>


>>I add 20kg mass which is 20000cm^3 and converted to m^3 and the addition mass is correct


this calculatuon  gives a density equal to that of water.

you have to decrease the volume of this mass in order to to increase the density!

<div>
yes 20kg is 20kg without any buoyancy factor applied to this weight.<br />
it could be 20kg of lead
</div>


yes 20kg is 20kg without any buoyancy factor applied to this weight.
it could be 20kg of lead

<div>
<div class="content wysiwyg-content">
Hi,I have a buoyancy question where I can work out a few things with formulas <br />
<br />
q)I dont know how to find out the additional part of the log submerged &nbsp;after placing a 20kg block on the wood<br />
I used Archimedes principles to find buoyancy force<br />
<br />
originally the log dimensions 0.2 X &nbsp;0.1m X 2m<br />
lies in water with density 1000 kg / m^3<br />
<br />
the part of the log submerged in the water has dimensions 0.2 X &nbsp;0.03m X 2m<br />
&nbsp;then placing 20kg mass has how much effect on submerging the log<br />
I have tried recalculating the density, Fb but I am getting stuck with extra mass <br />
<br />
<a href="http://hyperphysics.phy-astr.gsu.edu/hbase/pbuoy.html#c1" rel="ugc">http://hyperphysics.phy-astr.gsu.edu/hbase/pbuoy.html#c1</a><br />
<br />
q)how much weight do I need to fully submerge the log (min mass needed)?
</div>
</div>


Hi,I have a buoyancy question where I can work out a few things with formulas 

q)I dont know how to find out the additional part of the log submerged  after placing a 20kg block on the wood
I used Archimedes principles to find buoyancy force

originally the log dimensions 0.2 X  0.1m X 2m
lies in water with density 1000 kg / m^3

the part of the log submerged in the water has dimensions 0.2 X  0.03m X 2m
 then placing 20kg mass has how much effect on submerging the log
I have tried recalculating the density, Fb but I am getting stuck with extra mass 

http://hyperphysics.phy-astr.gsu.edu/hbase/pbuoy.html#c1

q)how much weight do I need to fully submerge the log (min mass needed)?

submerged log

The Math / Science topic primarily includes discussions of mathematics, physics, statistics and economic analysis, but also biology, chemistry and other sciences.