How to convert Excel column numbers into alphabetical characters

In Access I write data into an Excel file and need to address cells. For example I want to address the 50 th column and need to get the column address (in this example AX).

I found a solution which not proper work:  https://support.microsoft.com/de-de/kb/833402/en-us
Function ConvertToLetter(iCol As Integer) As String
   Dim iAlpha As Integer
   Dim iRemainder As Integer
   iAlpha = Int(iCol / 27)
   iRemainder = iCol - (iAlpha * 26)
   If iAlpha > 0 Then
      ConvertToLetter = Chr(iAlpha + 64)
   End If
   If iRemainder > 0 Then
      ConvertToLetter = ConvertToLetter & Chr(iRemainder + 64)
   End If
End Function

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53 results in A[ instead of BA .

Is there any proper solution?
User2008Asked:
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FarWestCommented:
of course you can reference cells using numbers
excamle
activesheet.cells(1,50) ' where 1 is row number and 50 is column number

also you use extract column part from this this

ActiveSheet.Cells(1, 50).Address
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Rgonzo1971Commented:
Of course Farwest answer is right

just to answer the question
Function ColumnLetter(ColNumber As Long) As String
    Dim lVar As Long
    Dim bVar As Byte
    Dim sVar As String

    lVar = ColNumber
    Do
        bVar = ((lVar - 1) Mod 26)
        sVar = Chr(bVar + 65) & sVar
        lVar = (lVar - bVar) \ 26
    Loop While lVar > 0
    ColumnLetter = sVar
End Function

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Regards
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FarWestCommented:
this is the implementation
Public Function GetColumnName(colindex As Integer) As String
GetColumnName = Split(Cells(1, colindex).Address, "$")(1)
End Function

Public Sub test()
Debug.Print GetColumnName(10)
End Sub

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FarWestCommented:
you can also use this single line of code if your column index will not exceed 701, that is not depend on worksheet reference or open sheet, and only if your column index will not exceed 701
Public Function GetColumnName(x As Integer) As String
GetColumnName = IIf(Int(x / 26) < 1, Chr(IIf(Int(x / 26) < 1, x, 1) + 64), Chr(Int(x / 26) + 64) + Chr((x - (Int(x / 26)) * 26) + 64))
End Function

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Rory ArchibaldCommented:
Or:
Function ColLtr(ByVal iCol As Long) As String
    If iCol > 0 Then ColLtr = ColLtr((iCol - 1) \ 26) & Chr(65 + (iCol - 1) Mod 26)
End Function

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which should cover any positive Long Integer value.
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FarWestCommented:
good job @Rory
0
User2008Author Commented:
It is  working perfectly in Access
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