php variable question

I'm sorry, that doesn't make sense to me. The first line is missing an echo or a variable assignement:

$mydate = date['d'];
//or
echo date['d'];

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The other line is just wrong

$$today = ; //where's the value?
$tomorrow = ; //where's the value?

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I don't undertsna what you mean when you say that sometimes it works. Anyway I strongly recommend yout to set error_reporting to E_ALL during development, so you'll get a lot of crucial infos directly by php engine

<?php
error_reporting(E_ALL);

//here the rest of code

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Do this with the actual script and you'll get a new vision of the universe ;-)

hi
thank for reply.
my script error

sorry

there is 2 file,  one in public path,   one is   test folder.

so the file in public folder  is error

php -q  p.php    will be error

php -q ./test/p.php  is  good,

you right,  must define the varible  with value.

Okay, and what is the error and what is the expected result? This is not clear to me from your question...

If you're new to PHP and want some good learning resources to help you get started, this article may show you some ways forward.
https://www.experts-exchange.com/Web_Development/Web_Languages-Standards/PHP/A_11769-And-by-the-way-I-am-new-to-PHP.html

Here is the original script with some notes that may be helpful.  A working version is included.
http://iconoun.com/demo/temp_loong.php

<?php // demo/temp_loong.php

/**
 * See http://www.experts-exchange.com/Programming/Languages/Scripting/PHP/Q_28639654.html
 */
error_reporting(E_ALL);


/**
 * THE ORIGINAL SCRIPT POST
 *
 * This script "does nothing" in that it does not produce any output or other evidence of work.
 *
 * In PHP, variables are assigned with a single equal sign.  The expression on the right of the
 * equal sign is evaluated, and the resulting value is placed into the variable on the left of
 * the equal sign.
 *
 * In PHP, the semi-colon is used to terminate statements.  A statement that is terminated after
 * the assignment (single equal sign) is meaningless and results in a PHP parse error.  The script
 * is not executed at all.
 *
 * Note that the original script, shown here, is encapsulated inside the comment statements and
 * has no effect, except to document the original code.
 *

<?php

 date( 'd' );

$today = ; $tomorrow = ;

?>

 */

/**
 * A MODIFIED VERSION OF THE SCRIPT
 *
 * In this script we determine and print the current day and the following day.
 *
 * Man Page References:
 * http://php.net/manual/en/function.time.php
 * http://php.net/manual/en/function.date.php
 * http://php.net/manual/en/function.strtotime.php
 * http://php.net/manual/en/function.var-dump.php
 */

// GET AN INTEGER TIMESTAMP REPRESENTING THE CURRENT TIME
$timestamp_of_now = time();

// FORMAT THE CURRENT DATE IN ISO-8601 STANDARD FORMAT
$printable_date_today = date('c', $timestamp_of_now);

// GET TOMORROW'S TIMESTAMP
$timestamp_of_tomorrow = strtotime($printable_date_today . ' + 1 DAY');

// GET TOMORROW'S DATE IN A DIFFERENT FORMAT
$printable_date_tomorrow = date('l, \t\h\e jS \o\f F, Y', $timestamp_of_tomorrow);

// SHOW THE WORK PRODUCTS
var_dump($printable_date_today);
var_dump($printable_date_tomorrow);

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? This doesn't make sense to me: how can the request 'Can you be a just a bit more verbose? ;-)' be a solution?