asp.net xml xmldocument node

Below I have xml and class I created but I do not know how to capture the value. Check the "?"

public DirDomain.Member MemberInfo(string ID)
        {
            #region Locate the XML File
            string filename = DomainCompany.memberXmlFileDir;
            #endregion
            #region Create Instance
            //create new instance of XmlDocument
            XmlDocument doc = new XmlDocument();
            #endregion
            #region Load the File
            //load from file
            doc.Load(filename);
            #endregion
            DirDomain.Member mm = new DirDomain.Member();        
            XmlNode selectedMember = doc.DocumentElement.SelectSingleNode("//Member[ID='" + ID + "']");
            foreach (XmlNode xn in selectedMember)
            {
                string mytype = ? //I want to get <Type> </Type> value
               
            }
            return mm;
        }


<?xml version="1.0" encoding="utf-8"?>
<Members>
  <Member>
    <Email>rickyandnary@gmail.com</Email>
    <Password>XwJ6uYW2yI/0O3vSe6NKeA==</Password>
    <FirstName>Rickasdfasdy</FirstName>
    <LastName>Yuasdfasdf</LastName>
    <Type>Gold</Type>
    <IsPrinterSellerCompany>NO</IsPrinterSellerCompany>
    <IsTechnician>NO</IsTechnician>
    <IsManufacturer>NO</IsManufacturer>
    <IsAdmin>NO</IsAdmin>
    <Status>ACTIVE</Status>
    <ID>F4JQoG7wsQmL9wMTrNzXncEhQbqzgMIB</ID>
  </Member>
</Members>
LVL 1
ITsolutionWizardAsked:
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Miguel OzSoftware EngineerCommented:
Use item property as shown below:
string mytype = selectedMember("Type").InnerText

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ITsolutionWizardAuthor Commented:
not working. see attachment
error10.jpg
0
Carl TawnSystems and Integration DeveloperCommented:
Firstly a loop won't work as you are only returning a single node, not a XmlNodeList. If you are only interested in the Type node then you can change your code to:
XmlNode selectedType = doc.DocumentElement.SelectSingleNode("//Member[ID='" + ID + "']/Type");
string mytype = selectedType.InnerText;

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Otherwise you would use:
XmlNode selectedMember = doc.DocumentElement.SelectSingleNode("//Member[ID='" + ID + "']");
string mytype = selectedMember["Type"].InnerText;

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