Remove parenthesis out of a data value

How do I remove these parenthesis within this data value in a sql script?
I want to remove anything that has a parenthesis in the value below.
From this:

and return this:

Also, how to create a script to remove:
From this:

and return this:

These will be used in populating 2 different columns within a table.

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slightwv (䄆 Netminder) Commented:
Replace ant value with a paran wirth a hard-coded value?

If so:
case when instr(column_name,'(') > 0 then '1U120231' else column_name end

Not sure I understand the second one either
Replace '7A120222-01' with '1U120231'?

literally replace:
replace(column_name,'7A120222-01', '1U120231')
MachinegunnerAuthor Commented:
No, these won't be a hard-coded value but a value within a column like - part_nbr.
I was just using those 'hard-coded' values as an example.

slightwv (䄆 Netminder) Commented:
I don't understand.

I don't see how I can turn '7A120222-01(903)' into '1U120231-01'
and  '7A120222-01' into '1U120231'

There doesn't seem to be any pattern/formula I can apply to do it.

Please provide sample data and expected results

For example:
drop table tab1 purge;
create table tab1(col1 varchar2(20));

insert into tab1 values('7A120222-01(903)');
insert into tab1 values('7A120222-01');
insert into tab1 values('Hello');

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Then based on the sample data, what are the results you expect?
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Gerwin Jansen, EE MVETopic Advisor Commented:
You can use this to remove the (923) part:
select regexp_replace (your_column,'\(([[:digit:]]{3})\)') from your_table;

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If you have the -01 part in another column:
select regexp_replace (other_column,'\-([[:digit:]]{2})$') from your_table;

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Are your 2 examples in separate columns? Then you can combine the 2 above:
regexp_replace (your_column,'\(([[:digit:]]{3})\)'),
regexp_replace (other_column,'\-([[:digit:]]{2})$')
from your_table;

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Naveen KumarProduction Manager / Application Support ManagerCommented:
'7A120222-01(903)' -->  and return this:  '1U120231-01'

 '7A120222-01' -->  and return this: '1U120231'

Can you explain your logic on how to get the output with which we can come up with the sql query.

awking00Information Technology SpecialistCommented:
Removing the parentheses at the end is easily accomplished using regular expressions or even a simply substring, for example, substr(yourcol,instr(yourcol,'(') - 1) Replacing a value of '7A120222-01' with '1U120231' requires a lot more description. Can you provide more sample data with multiple values plus your expected results and the criteria for thier detemination.
awking00Information Technology SpecialistCommented:
The substr example should have been -
 substr(yourcol,instr(yourcol,1, '(') - 1
slightwv (䄆 Netminder) Commented:
>>The substr example should have been -

FYI:  You can edit your post as long as no one has posted after you...

Given this is now three people that has pretty much said the same thing, I doubt the asker saw that post before you could have edited it...  ;)
awking00Information Technology SpecialistCommented:
slightwv, I wish I could have edited it but since this website changed, I don't seem to have that option along with many others, including the acceptance of solutions, using the bold, italics, etc, attaching files, and putting cod into snippets. I have a feeling this is all due to my outdated version of IE that I'm not allowed to change.
MachinegunnerAuthor Commented:
Thank you for all the replies.
I have tried the regexp_replace expression for the part_nbr replacement.  As seen below.
I had to move part data from another system to another and by using the part_nbr, I could
now update 2 other columns - document_nbr and eng_part_nbr.

Here are the updates I used:
--get rid of the partners with parenthesis... Eng_Part_Nbr column...
update part master
set eng_part_nbr = regexp_replace(part_nbr,'\(([[:digit:]]{3})\)')
where part_nbr like '%(%'
and eng_part_nbr is null;

--get rid of the eng_part_nbr from the hyphen... Document_Nbr column...
update part_master
set document_nbr = regexp_replace(eng_part_nbr,'\-([[:digit:]]{2})$')
where document_nbr is null
and eng_part_nbr is not null;
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