Triangle Calculations to get all possible permutations

Hello,
I am trying to calculate all possible permutations with a function.
I have 100 numbers for each of the 3 products example

>network speed
1.2354
1.2885
1.3569

>network latency
0.263
0.214
0.325

>duration
5.323
6.525
4.784
etc..

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if I wanted to get all combinations together I would have to do 100*100*100 = 1,000,000
what would be the best approach for speed and stability ?
Daniel SufreAsked:
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Mike EghtebasDatabase and Application DeveloperCommented:
Assuming you have a loop with access to three point for each triangle:

Single aX = 0;
Single aY= 0;
Single bX = 3;
Single bY = 4;
Single cX = 0;
Single cY = 4;

Single base = findBase(aX, aY, bX, bY);
Single height = findBase(aX, aY, bX, bY, cX, cY);

Single area = (base * height)/2.0;
.
.
private single findBase(aX, aY, bX, bY)
{
single b = ((aX-bX)^2 + (aY-bY)^2)^.05;
return b;
}

I will post findBase() function shortly.

Mike
Mike EghtebasDatabase and Application DeveloperCommented:
This is the tested solution and it works.
        private void button1_Click(object sender, EventArgs e)
        {
            Single aX = 0;
            Single aY= 0;
            Single bX = 3;
            Single bY = 4;
            Single cX = 0;
            Single cY = 4;

            Single b =findBase(aX, aY, bX, bY);

            Single height = findHeight(aX, aY, bX, bY, cX, cY);

            Single area = (Single)((b * height) / 2.0);
           MessageBox.Show(area.ToString());
        }
        private Single findBase(Single aX, Single aY, Single bX, Single bY)
        {
            return (Single)Math.Pow((Math.Pow((aX - bX), 2.0) + Math.Pow((aY - bY), 2.0)), 0.5);
        }
        private Single findHeight(Single aX, Single aY, Single bX, Single bY, Single cX, Single cY)
        {
            Single m1 = (Single)(aY - bY) / (Single)(aX - bX);
            Single m2 = -(1/m1);
            Single hX = (m1*aX- m2*cX + cY - aY)/(m1-m2);
            Single hY = m1*hX - m1 * aX + aY;

            return (Single)Math.Pow((Math.Pow((cX - hX), 2.0) + Math.Pow((cY - hY), 2.0)), 0.5);
        }

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Mike EghtebasDatabase and Application DeveloperCommented:
I just noticed; you were not looking for triangle area I guess. The question was not very clear so you got the solution possibly with no use for you. If so, consider deleting it and posting it again with some clear description.

Thanks,

Mike
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