PHP Checking a variable

Is there a way to check if a variable contains a value, without it matching exactly?

Meaning, I have the following line of code:
<?php
if (!empty($error_status['ExtendedStatusCd']) && $error_status['ExtendedStatusCd'] == "OFAC Hit, Score:100.00")

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However, I would like it to check if it has "OFAC Hit"  not the rest.  Something like this:
<?php
if (!empty($error_status['ExtendedStatusCd']) && $error_status['ExtendedStatusCd'] == "OFAC Hit%")

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LVL 7
rgranlundAsked:
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Marco GasiFreelancerCommented:
Use strpos:

$pos = strpos($error_status['ExtendedStatusCd', "OFAC Hit"]); 
if (!empty($error_status['ExtendedStatusCd']) && $pos  !== false )

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0
Marco GasiFreelancerCommented:
Learn here about http://php.net/strpos
0
Radostin NonkinOwnerCommented:
Solution #1 - using regular expression match:
$regexMatch = preg_match("/^(OFAC Hit).+/", $error_status['ExtendedStatusCd']) ? true : false;
if (!empty($error_status['ExtendedStatusCd']) && $regexMatch)

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Solution #2 - matching against part of the string:
$matchSubstring = substr($error_status['ExtendedStatusCd'], 0, 8) == "OFAC Hit" ? true : false;
if (!empty($error_status['ExtendedStatusCd']) && $matchSubstring)

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0

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Chris HarteThaumaturgeCommented:
I would have thought strstr() would be more suitable

http://php.net/manual/en/function.strstr.php

if (!empty($error_status['ExtendedStatusCd'])
     && strstr ($error_status['ExtendedStatusCd'], "OFAC Hit"))

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0
Marco GasiFreelancerCommented:
Ooops, sorry rgranlund, I mystyped the statement:
$pos = strpos($error_status['ExtendedStatusCd'], "OFAC Hit"); 
if (!empty($error_status['ExtendedStatusCd']) && $pos  !== false )

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Glad you have solved anyway :-)
0
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