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Yes, just use $(&quot;#someElement&quot;).addClass<wbr />(&quot;someStyl<wbr />e&quot;);<br />
Please note when you use addClass the parameter is the class name and not a class selector (means no need for the dot)
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Yes, just use $("#someElement").addClass("someStyle");
Please note when you use addClass the parameter is the class name and not a class selector (means no need for the dot)

<div>
Brian, thanks for responding, but I don't think you read my question carefully. <br />
<br />
Notice I bold-faced <b>RUNTIME </b>and <b>ON THE FLY</b>.<br />
<br />
I wanted to know if there was a way to still use addClass(&quot;someStyle&quot;) that somehow represents CSS styles created entirely within jQuery and not something defined in an external style sheet or within a &lt;style&gt; tag.
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Brian, thanks for responding, but I don't think you read my question carefully.

Notice I bold-faced RUNTIME and ON THE FLY.

I wanted to know if there was a way to still use addClass("someStyle") that somehow represents CSS styles created entirely within jQuery and not something defined in an external style sheet or within a <style> tag.

<div>
Exactly what I was looking for, thanks much, Brian!
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Exactly what I was looking for, thanks much, Brian!

<div>
Glad to help. &nbsp;Thanks for the points.
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<div>
<div class="content wysiwyg-content">
Is there a way for me to create something like this in jQuery during <b>RUNTIME</b>, i.e., <b>ON THE FLY</b>:<br />
<br />

<pre><code id="code-10-28648677-1">.someStyle {
    color: yellow;
    background: red;
    border: 1px solid blue;
}</code></pre>
<br />
and then be able to reference the whole set of styles as .addClass(&quot;.someStyle&quot;)?<br />
<br />
In other words, I don't want to have to do it this way: $(&quot;#someElement&quot;).css(&quot;col<wbr />or&quot;, &quot;yellow&quot;), and so on.<br />
<br />
Thanks.
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</div>


Is there a way for me to create something like this in jQuery during RUNTIME, i.e., ON THE FLY:

(CODE)

and then be able to reference the whole set of styles as .addClass(".someStyle")?

In other words, I don't want to have to do it this way: $("#someElement").css("color", "yellow"), and so on.

Thanks.

jQuery question about .css()

jQuery (Core) is a cross-browser JavaScript library that provides abstractions for common client-side tasks such as Document Object Model (DOM) traversal, DOM manipulation, event handling, animation and Ajax. jQuery also provides a platform to create plugins that extend jQuery's capabilities beyond those already provided by the library.

jQuery

Cascading Style Sheets (CSS) is a language used for describing the look and formatting of a document written in a markup language. Usually used to change web pages and user interfaces written in HTML, it can also be applied to any kind of XML document. CSS is designed primarily to distinguish the content of a document from its presentation.