union query (I assume)

Dear experts -
I have 1 table ('timesheet_summary') that contains a date (always a Monday), a person ID (numeric), a total hours, and a few other fields.
I have another table (calendar table) that contains all Mondays.
What I want to do is populate a new table (temp table) that, for a given period (I would like to have the flexibility of specifying this) would generate one record for every Monday; it would grab all records that exist in the 'timesheet_summary' table FOR THAT PERSON, and would create a new record for every Monday in that period that didn't exist in the 'timesheet_summary' table.
person = '13'; date range = from 2 March 2015 to 30 Marc h 2015 (five Mondays)
timesheet_summary table contains these records
2 March 2015; person = 13; total = 10 hours
16 March 2015; person = 13; total = 8 hours

Now, when I run this query (union query?) the output would be:
2 March 2015; person = 13; total = 10 hours
9 March 2015; person = 13
16 March 2015; person = 13; total = 8 hours
23 March 2015; person = 13
30 March 2015; person = 13

Any suggestions are appreciated...
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You can do this with a tally table (numbers table).  I show an example of generating dates in this article:
In my opinion a simple left join will return the query you are after. You can even create it with the built-in Query Wizard. The resulting query will be similar to this:
SELECT calendar.dt, [ParamPerson] as PersonID, timesheet_summary.totalHours
FROM calendar LEFT JOIN timesheet_summary
ON calendar.dt = timesheet_summary.dt
WHERE timesheet_summary.PersonID = [ParamPerson] AND
calendar.dt >= [ParamFromDate] AND calendar.dt < [ParamToDate]

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PortletPaulEE Topic AdvisorCommented:
if that calendar table does contain all Mondays then the left join will be sufficient (as proposed by chaau)

if that calendar table has gaps, then a left join will not be sufficient and you will need to generate the Mondays
terpsichoreAuthor Commented:
this seems to do the trick. thank you.
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