terpsichore
asked on
union query (I assume)
Dear experts -
I have 1 table ('timesheet_summary') that contains a date (always a Monday), a person ID (numeric), a total hours, and a few other fields.
I have another table (calendar table) that contains all Mondays.
What I want to do is populate a new table (temp table) that, for a given period (I would like to have the flexibility of specifying this) would generate one record for every Monday; it would grab all records that exist in the 'timesheet_summary' table FOR THAT PERSON, and would create a new record for every Monday in that period that didn't exist in the 'timesheet_summary' table.
EXAMPLE:
person = '13'; date range = from 2 March 2015 to 30 Marc h 2015 (five Mondays)
timesheet_summary table contains these records
2 March 2015; person = 13; total = 10 hours
16 March 2015; person = 13; total = 8 hours
Now, when I run this query (union query?) the output would be:
2 March 2015; person = 13; total = 10 hours
9 March 2015; person = 13
16 March 2015; person = 13; total = 8 hours
23 March 2015; person = 13
30 March 2015; person = 13
Any suggestions are appreciated...
I have 1 table ('timesheet_summary') that contains a date (always a Monday), a person ID (numeric), a total hours, and a few other fields.
I have another table (calendar table) that contains all Mondays.
What I want to do is populate a new table (temp table) that, for a given period (I would like to have the flexibility of specifying this) would generate one record for every Monday; it would grab all records that exist in the 'timesheet_summary' table FOR THAT PERSON, and would create a new record for every Monday in that period that didn't exist in the 'timesheet_summary' table.
EXAMPLE:
person = '13'; date range = from 2 March 2015 to 30 Marc h 2015 (five Mondays)
timesheet_summary table contains these records
2 March 2015; person = 13; total = 10 hours
16 March 2015; person = 13; total = 8 hours
Now, when I run this query (union query?) the output would be:
2 March 2015; person = 13; total = 10 hours
9 March 2015; person = 13
16 March 2015; person = 13; total = 8 hours
23 March 2015; person = 13
30 March 2015; person = 13
Any suggestions are appreciated...
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if that calendar table does contain all Mondays then the left join will be sufficient (as proposed by chaau)
if that calendar table has gaps, then a left join will not be sufficient and you will need to generate the Mondays
if that calendar table has gaps, then a left join will not be sufficient and you will need to generate the Mondays
ASKER
this seems to do the trick. thank you.
http:A_5410.html