Editing a column in a csv File

I'm need to export users from export and have the resulting CSV file in a certain format. What I so far is:

Get-ADUser -filter * -Properties * |     Select  @{N='rcscardcode';E={$_.rcscardcode.Substring(0,10) }},rcsidnumber,givenname,surname,RCSsecurityGroup,description,rcsuserphoto | export-csv C:\Users\johncolfer\Desktop\TempStuff\Active-dir\manual-export2.csv  

This is 1 row of the results:
1500006790      50000679      Muna      Sabah      1      Lecturers Office      \\fileserver10\RCSIPhoto\50000679.jpg

What I want to do is drop the "\\fileserver10\RCSIPhoto\" in the "rcsuserphoto" column and have the following results:

1500006790      50000679      Muna      Sabah      1      Lecturers Office      50000679.jpg

It's probably a simple solution but am struggling with it at the moment.


johncolferSecurity ConsultantAsked:
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Basically the same way you created the rcscardcode property:
Get-ADUser -filter * -Properties * | Select-Object -Property `
	@{N='rcscardcode'; E={$_.rcscardcode.Substring(0,10) }},
	@{N='rcsuserphoto'; E={Split-Path -Path $_.rcsuserphoto -Leaf}} | Export-Csv -Path C:\Users\johncolfer\Desktop\TempStuff\Active-dir\manual-export2.csv -NoTypeInformation

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johncolferSecurity ConsultantAuthor Commented:
Great solution and very prompt. Thanks a million.
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