column A has  a list of codes that can start with either "1", "2", "4', and "6". Column B needs to have a function that says if A1 starts with 1 then "A", if A1 starts with "2" then "B", if A1 starts with "4" then "C" and if A1 starts with "6" then "D"

Example:  A1= 201905555  - B1 should say "B"
                  A2=401303245 - B2 should say "C"
                  A3=600637985 - B3 should say "D"

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John EastonDirectorCommented:
If you intend this to get more complex then I would use VLookup with a hidden lookup table.  But assuming the list is not going to get any longer I would use the following formula in B1:

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Ejgil HedegaardCommented:
You could make some nested if statements, but shorter like this, using the character codes, A=65, B=66 etc.
Tj aCommented:
Try this

=IF(LEFT(A1,1) = "2", "B", IF(LEFT(A1,1)= "4", "C", IF(LEFT(A1,1)="6", "D", "")))

then drag down the formula or try a Vlookup but this is smipler.
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Qlemo"Batchelor", Developer and EE Topic AdvisorCommented:
You could also use
=CHOICE(LEFT(A1,1), "A", "B",,"C",,"D")

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or a lookup

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LadkissonAuthor Commented:
Great formulas! Thanks!
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