Assistance with bash, include command in output to a file

Hi Team,

   I just need to create a simple  script that captures some commands and output to a file. In my code below, it is just sending the actual outputs and not the command itself, making it difficult to note the start and end output stream of each command.  In the example below, I just have 5 shell the final script, there will be over 50.

[root@testing ~]# cat
BASEFILE=BASELINE_$(date '+%d_%b_%Y_%H_%M_%S').txt
uptime >> $BASEFILE 2>&1 
who >> $BASEFILE 2>&1
last -n 100 >> $BASEFILE 2>&1
free -m  >> $BASEFILE 2>&1
df -h  >> $BASEFILE 2>&1

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The file just shows the raw output of the individual commands, and not the commands that invoked them, making it difficult to find the start and end of each output block.

[root@testing ~]# cat BASELINE_26_Apr_2015_09_43_46.txt
 09:43:46 up  1:16,  4 users,  load average: 0.00, 0.00, 0.00
au157 tty1         2015-04-26 18:47 (:0)
au157 pts/0        2015-04-26 18:47 (:0.0)
au157 pts/1        2015-04-26 08:48 (
au157pts/2        2015-04-26 09:01 (

wtmp begins Sun Apr 26 09:39:02 2015
             total       used       free     shared    buffers     cached
Mem:          1894        618       1275          4         60        325
-/+ buffers/cache:        232       1662
Swap:         4063          0       4063
Filesystem            Size  Used Avail Use% Mounted on
                       35G  4.1G   30G  13% /
tmpfs                 948M   80K  948M   1% /dev/shm
/dev/sda1             477M   68M  385M  15% /boot

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Thanks very much.
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BASEFILE=BASELINE_$(date '+%d_%b_%Y_%H_%M_%S').txt
exec >> $BASEFILE 2>&1
set -x
last -n 100
free -m
df -h

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rleyba828Author Commented:
Yes, this second variation works well.   thanks very much.
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Shell Scripting

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