Oracle SQL

I have a following table with the datasets as a example.

Date                            Type
01/02/2014 12:32     GEO
01/03/2014  14:43    GEO
01/04/2014  19:34    GEO
01/07/2014   01:23    SCI
01/07/2014   02:23     ENG

02/05/2015 12:33 GEO
02/02/2015 01:33 MAT

I want to group the date by month and the result should be like this:

Month                 GEO  SCI   MAT ENG   Total
01/01/2014         3        1      0       1         5
02/01/2015         1        0      1       0          2
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Haris DulicIT ArchitectCommented:

try this:
select date as Date, sum(a) as GEO, sum(b) as SCI, sum(c) as MAT, sum(d) as ENG, sum(a+b+c+d) as TOTAL
from (
select to_char(date,'mm/dd/yyyy') as date, count(1) as a , 0 as b, 0 as c, 0 as d from TABLE_NAME where type ='GEO'
select to_char(date,'mm/dd/yyyy') as date, 0 as a , count(1) as b, 0 as c, 0 as d from TABLE_NAME where type ='SCI'
select to_char(date,'mm/dd/yyyy') as date, 0 as a , 0 as b, count(1) as c, 0 as d from TABLE_NAME where type ='MAT'
select to_char(date,'mm/dd/yyyy') as date, 0 as a , 0 as b, 0 as c, count(1) as d from TABLE_NAME where type ='ENG'
from) a
group by date

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SELECT TRUNC(yourdate, 'mm') month,
         COUNT(DECODE(yourtype, 'GEO', 1)) geo,
         COUNT(DECODE(yourtype, 'SCI', 1)) sci,
         COUNT(DECODE(yourtype, 'MAT', 1)) mat,
         COUNT(DECODE(yourtype, 'ENG', 1)) eng,
         COUNT(*) total
    FROM yourtable
GROUP BY TRUNC(yourdate, 'mm')


SELECT month,geo,sci,mat,eng,geo+sci+mat+eng total
 FROM (SELECT trunc(yourdate,'mm') month, yourtype FROM yourtable )
    PIVOT(COUNT(*) FOR yourtype IN ('GEO' geo,'SCI' sci,'MAT' mat,'ENG' eng))
ORDER BY month;
Mark GeerlingsDatabase AdministratorCommented:
The output you are asking for is called a "matrix" or "cross-tab" report.  Simple SQL does not do this.  So, you need the more-complex examples like what others have suggested, or you need to use a reporting tool that can do this for you.
if the expected columns are known before hand it can be done,  as illustrated above in 2 different forms.

you could also do a bunch of self-joins or unions but that's horribly inefficient
Steve WalesSenior Database AdministratorCommented:
This question has been classified as abandoned and is closed as part of the Cleanup Program. See the recommendation for more details.
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