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what is the role of "bash -s"?

I see following line to install chefdk

curl -L https://chef.io/chef/install.sh | sudo bash -s -- -P chefdk

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I want to understand that does "bash -s -- -P chefdk" does and how does '-P' gets supplied as option to 'install.sh' and not to 'bash' ?

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ozo

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woolmilkporc

-s makes bash read commands (the "install.sh" code as downloaded by "curl") from stdin, and accept positional parameters nonetheless.

"--" lets bash treat everything which follows as positional parameters instead of options.

bash will set the variables "$1" and "$2" of the "install.sh" code to "-P" and to "chefdk", respectively.

tel2

Hi woolmilkporc,

> "bash will set the variables "$1" and "$2" of the "install.sh" code to "-P" or to "chefdk", respectively."

Does this mean that after running that whole one-liner, the 1st & 2nd "words" (for lack of a better word) of the output of the curl command will be accessible via $1 & $2?

Also, any ideas why "sudo" is being used here? Does it imply the user doesn't even have access to run bash without sudo?

ozo

Does this mean that after running that whole one-liner, the 1st & 2nd "words" (for lack of a better word) of the output of the curl command will be accessible via $1 & $2?

Also, any ideas why "sudo" is being used here?

Perhaps so that the commands in https://chef.io/chef/install.sh can be run as root

Does it imply the user doesn't even have access to run bash without sudo?

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