(0) in final of javascript function node.js

Hi,

I see a part of a code with something like this

(function(arg1,arg2){

//....some code

})(0)

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what means the (0) after the function and with the function is enclosed in parenthesis?
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joyacv2Asked:
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Alexandre SimõesManager / Technology SpecialistCommented:
Well, I don't know if this code is actually just an example because in this specific example it doesn't make any sense.

What you have here is a self invoking function.
The main objective is to prevent declarations in the global namespace on an initialization piece of code.
As this is an anonymous function, there's no way to call it after, so the sole objective is to wrap it in parentheses and call it right away by adding () right after.

Passing arguments into this function (like you're passing the 0) is mainly used to avoid naming collisions. For instance, you'll find this a lot in jquery plug-ins to avoid collisions with $.

Here's a nice article if you want to further read about self invoking functions : https://sarfraznawaz.wordpress.com/2012/01/26/javascript-self-invoking-functions/
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Hans LangerCommented:
so, since you can assign a function into a variable like this:
var func1 = myFunction(arg1){ return arg1 } 

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and then execute it:
var result = func1(1)  //or var result =(func1)(1)
//result value will be = 1

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you can do the same without assigning it to a variable and just execute it after being created.

//same as (func1)()
(function(arg1){return arg1})(0) <-- Executed with the first argument = 0

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Is not very usefull but some people prefer to use it like that for readability and  save memory space.
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joyacv2Author Commented:
thank you to all!
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