Do I need terminating resistor in my CAN setup ?

I have Two PC based CAN Applications installed in my computer, CANoe and a proprietary application.  
CANoe application needs to talk over 11-bit CAN to embedded target board via Vector VN1630 CANCase.  
Proprietary application needs to talk over 11-bit CAN to embedded target board via a dongle.

Target Board, CANCase, and dongle need to have same CAN connection.  The purpose of CANCase is to only monitor message exchanges between dongle and target board.  CANCase won't transmit any messages.

Do I need a terminating resistor in my setup ?   If yes, exactly where should it be inserted ?  What should be the value, 120K Ohms ?
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naseeamAuthor Commented:
My baud rate is 125000
naseeamAuthor Commented:
Bus length is about 2 feet.  

It's a low speed CAN Network.
A diagram is worth 1000 words.
Do the devices at the ends of the bus have optional terminations?
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naseeamAuthor Commented:
>>  Do the devices at the ends of the bus have optional terminations?

I didn't understand the question.
The best advice from
     The Standard defines a single line of twisted-pair cable with the network topology as shown in Figure 6.
     It is terminated at both ends with 120-Ω resistors, which match the characteristic impedance of the line
     to prevent signal reflections.

Good advice from
     You can accomplish the termination (on a small network) with a single 60 ohm ...

Maybe adequate advice from the second source
     For short cables, you can often get by without any termination.

You definitely have a short cable.  At 125 kHz, one wavelength would be 2400 meters.

In order of ease.
    Do nothing and see it works.
    Put a 60 ohm resistor anywhere in the network.
    Put two 120 ohm resistors at the endpoints of the network.

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>>  Do the devices at the ends of the bus have optional terminations?

Many times a device will have a jumper to connect a terminating resistor when the device is at one of the endpoints.
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